Its a double elimination.
Since these carbons are secondary they can undergo E1 or E2, depending on the strength of the base used, if the adjacent hydrogen is stericly hindered (blocked by a bulky group).
Using a strong base such as -OH (from K+OH-)
You have the Bromine attack the K+, making a carbocation, then have the H of the adjacent carbon leave (donate) its electron to the carbocation creating a double bond, and have the -OH attach to that leaving Hydrogen; forming water as a result.
This leaves you with a bromine attached to one carbon on the double bond, and a Hydrogen on the other. So you just repeat those steps again. Leaving you with the Diphenlacetlyene.
Which is just PhC(triple bond)CPh + HOH + 2KBr
It is possible to make KOH work for the double dehydrohalogenation of an alkane if the base is in a high concentration. If a solvent like triethylene glycol is used, KOH will be less solvated than in solutions of say water, and therefore act as a stronger base.
The reaction of 1-bromobutane is proceeding via an SN2 mechanism.
The mechanism consistent with the experimental reaction profile shown here is likely a multi-step reaction involving intermediates and transition states.
The reaction of 1-bromobutane is more likely to proceed via an SN2 mechanism.
The rate determining step graph shows the slowest step in a reaction, which determines the overall rate of the reaction. This step often indicates the mechanism of the reaction, as it is typically the step with the highest activation energy.
mechanism. mechanism.
It is possible to make KOH work for the double dehydrohalogenation of an alkane if the base is in a high concentration. If a solvent like triethylene glycol is used, KOH will be less solvated than in solutions of say water, and therefore act as a stronger base.
what is the reaction mechanism between wagner's reagent and alkaloids
Each step in a reaction mechanism is referred to as an elementary step.
The reaction mechanism between these two chemicals involved an aromatic carbon. The typical classification of this reaction is called a condensation.
The reaction of 1-bromobutane is proceeding via an SN2 mechanism.
The transition state is not a step in a reaction mechanism; it is a high-energy state that exists at the peak of the reaction potential energy diagram. The slowest step in a reaction mechanism is often referred to as the rate-determining step, which has the highest activation energy and determines the overall rate of the reaction.
No. This is a reaction, but not a reaction mechanism. The mechanism would should the individual steps or alterations that take place with the HCl dissociating, and the electrons moving from one place to another, etc.
The mechanism consistent with the experimental reaction profile shown here is likely a multi-step reaction involving intermediates and transition states.
Ans~ C for plato~ reaction mechanism
The reaction of 1-bromobutane is more likely to proceed via an SN2 mechanism.
A plausible reaction mechanism should involve intermediates that are stable under the reaction conditions, follow the principle of microscopic reversibility, and be consistent with the overall stoichiometry of the reaction.