+1 (Apex 2021)
1+
Atomic number is the number of protons in the nucleus of an atom. Therefore, sodium's atomic number is always 11, even if it loses 1 electron. However, when a sodium atom loses 1 electron, it will form an ion with a 1+ charge.
The atomic number of rubidium is 37. That means it has 37 protons and 37 electrons. After we fill in the first 37 orbitals with electrons, we get the configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1. Since 5 is the highest numbered shell, rubidium has 1 valence electron.
This ion will have a charge of -1. The atomic number is the number of protons in the atom's nucleus. A neutral atom will have a number of electrons equal to the atomic number, which is the number of protons in that nucleus. Since you have an extra electron your atom has a negative charge of one electron's worth, or minus one, which is 1.6 x 10-19 coulombs.
forgive me if i do not remember exactly but i believe a Rubidium atom contains 19 electrons 20 neutrons and 19 protons
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Francium is radioactive and rubidium not. Also the electron configuration, atomic number, physical properties, hazards etc. are different.
Rubidium is a metal element. Atomic mass of it is 85.46.
Rubidium has an atomic number of 37, making it an alkali metal. This means that its last shell is an s with only one electron. The full notation is [Kr] 5s1.
atomic # = protons atomic mass - atomic number = neutrons atomic # - charge = electrons
Rubidium has an atomic number of 37, making it an alkali metal. This means that its last shell is an s with only one electron. The full notation is [Kr] 5s1.
Rubidium is an element (atomic number 37).
Rubidium is an element (atomic number 37).
Rubidium is an element (atomic number 37).
37
The atomic radius depends on the the number of electron shells, total negative charge, positive charge of the nucleus, atomic mass.
Atomic number is the number of protons in the nucleus of an atom. Therefore, sodium's atomic number is always 11, even if it loses 1 electron. However, when a sodium atom loses 1 electron, it will form an ion with a 1+ charge.
The atomic number of rubidium is 37. That means it has 37 protons and 37 electrons. After we fill in the first 37 orbitals with electrons, we get the configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1. Since 5 is the highest numbered shell, rubidium has 1 valence electron.