In this scenario, there would be a 50% chance of Cc and 50% chance of cc. Half of the offspring would have a cleft chin, and half would have a normal chin.?æ
Cc x cc would yield 50% Cc and 50% cc, so half of the offspring would have a cleft chin and half would have a normal chin.
Cc x cc= cc Cc
covalent bond
Neutralization is the reaction between an acid and an alkali. Neutralization usually results in the formation of a salt from the reaction.
Glucose - one of the results of photosynthesis Sugar - refined glucose
Hydrogen bonds form between water molecules due to water's polarity.
No. The mutual attractions between many positive ions and many negative ions result in a compound with ionic bonds.
The expected results are half Cc and half cc.
Pp 50% and pp 50% .
The offspring are genetic copies of their parents (and it's genotypes).
In this scenario, there would be a 50% chance of Cc and 50% chance of cc. Half of the offspring would have a cleft chin, and half would have a normal chin.?æ
On the outside of the Punnett Square you put the genotype or two alleles of the parents.
The expected phenotype for a Mendal F1 monohybrid cross is 3:1. Looking at heterozygous parents (F1) who share the same dominant trait, e.g. Straight tail.Crossing two heterozygous parents from the F1 generation results in an F2 generation that produces a 75% chance for the appearance of the dominant phenotype, of which two-thirds are heterozygous, and a 25% chance for the appearance of the recessive phenotype, giving the ratio 3;1.Inheritance pattern of dominant and recessive phenotypes when each parent is homozygous for either the dominant or recessive trait. All members of the F1generation are heterozygous and share the same dominant phenotype, while the F2generation exhibits a 3:1 ratio of dominant to recessive phenotypes.
Genotypes on random mating of gametes
Possible genotypes would be AA and Aa. Phenotypes cannot be determined here because they are the physical, observable results of a genotype.
The results in the offspring hinge on the genetic make up of the parents. Each expressed trait is either the result of a dominant or recessive phenotype. The relative dominance or recessiveness of the alleles doesn't change only the rate at which they are expressed based on the allele present for each obseerved trait in the parents.
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
It would depend on if the dominant genes are the same or different. Say the dominant alleles were different. In this case, they are co-dominant. If they are the same and both dominant homosytus.
Yy