freezing point depression ..
The effect of a solute on the freezing point and boiling point of a solvent is related to what is known as the colligative property. Upon addition of the solute, the freezing point will be lowered, and the boiling point will be increased. The magnitude of the change will depend on the solute and how many particles it forms upon dissolving, and on the nature of the solvent and the freezing/boiling point constant for that solvent.
The concentration of solute in the solvent is most responsible for changing the boiling and freezing points. When a solute is added to a solvent, it disrupts the normal intermolecular forces between solvent molecules, which results in a change in the boiling and freezing points of the solvent.
Molar mass determination through freezing point depression involves measuring the decrease in freezing point of a solvent when a solute is added. By comparing the change in freezing point to the known properties of the solvent, the molar mass of the solute can be calculated using the formula Tf Kf m, where Tf is the change in freezing point, Kf is the cryoscopic constant of the solvent, and m is the molality of the solute.
not sure about it, for example; take two different types of oil (not water) consider the first liquid is 'x' and other is 'y' you want to change the freezing point of 'x' by adding 'y' slowly you can imagine the equations and other because i am a poor 'Indian' 'plus two' (standard education) my English also very bad.
The molar mass of a solute can be determined using freezing point depression by measuring the change in freezing point of a solvent when the solute is added. By using the formula Tf Kf m, where Tf is the change in freezing point, Kf is the cryoscopic constant of the solvent, and m is the molality of the solution, the molar mass of the solute can be calculated.
The effect of a solute on the freezing point and boiling point of a solvent is related to what is known as the colligative property. Upon addition of the solute, the freezing point will be lowered, and the boiling point will be increased. The magnitude of the change will depend on the solute and how many particles it forms upon dissolving, and on the nature of the solvent and the freezing/boiling point constant for that solvent.
The concentration of solute in the solvent is most responsible for changing the boiling and freezing points. When a solute is added to a solvent, it disrupts the normal intermolecular forces between solvent molecules, which results in a change in the boiling and freezing points of the solvent.
Molar mass determination through freezing point depression involves measuring the decrease in freezing point of a solvent when a solute is added. By comparing the change in freezing point to the known properties of the solvent, the molar mass of the solute can be calculated using the formula Tf Kf m, where Tf is the change in freezing point, Kf is the cryoscopic constant of the solvent, and m is the molality of the solute.
not sure about it, for example; take two different types of oil (not water) consider the first liquid is 'x' and other is 'y' you want to change the freezing point of 'x' by adding 'y' slowly you can imagine the equations and other because i am a poor 'Indian' 'plus two' (standard education) my English also very bad.
The molar mass of a solute can be determined using freezing point depression by measuring the change in freezing point of a solvent when the solute is added. By using the formula Tf Kf m, where Tf is the change in freezing point, Kf is the cryoscopic constant of the solvent, and m is the molality of the solution, the molar mass of the solute can be calculated.
It's called freezing. Think of water to ice. Freezing.
- Melting point change. ^.^
This type of change is called freezing
a liquid to a solid is called the melting point:-)
The change is called freezing.
This is the phase change called freezing.
Yes, solute particles change the freezing and boiling points of solutions. This is known as colligative properties, where the presence of the solute affects the physical properties of the solvent. The freezing point decreases and the boiling point increases compared to the pure solvent.