What is the product of the alpha decay of berkelium?

Answer 1

Alpha decay of any radionuclide would reduce the atomic number by 2 and reduce the Atomic Mass number by 4. As such, berkelium would decay by alpha emission to americium.

Note that not all isotopes of berkelium decay by alpha emission. In terms of percentages, the most predominate example is ...

97247Bk --> (T1/2 = 1380 years) --> 95243Am + 24He2+

Answer 2

Alpha decay happens when a radioactive atom emits a particle with two protons and two neutrons. Berkelium, with an atomic number of 97, has 97 protons. So when berkelium undergoes alpha decay, it loses two protons, and becomes an atom with 95 protons, atomic number 95, which is americium. Since a total of four nucleons are emitted in the process, the isotope number is four less then what the original atom had.

Answer 3

The product of the alpha decay of Berkelium is Californium-249. In the decay process, an alpha particle (Helium-4 nucleus) is emitted, resulting in a new element with an atomic number that is two less than the original element.

Answer 4

bismuth-210 decays (through beta-emission) with a half-life of 5 days to polonium-210

A+ . . . polonium

Answer 5

Americium isotopes

Answer 6

Californium