The reaction between acetic acid and NH4OH?

Answer 1

The result of a reaction with acetic acid and CH3NH2 is a product known as N-methylethanamide. This only happens if a high enough temperature is used, otherwise a reaction may not occur at all.

Answer 2

The reaction between acetic acid and ammonia is an acid-base reaction. The proton from the acid reacts with the hydroxide in the solution; the products are the acetate ion and water, with the ammonia ion not actually participating in the reaction.

Answer 3

First of all it is better not to speak of NH4OH in solution but of dissolved NH3 *)

CH3COOH + NH3 (+ H2O) <--> CH3COO- + NH4+ (+ H2O)

Both acetic acid and ammonia are weak acid/base and so are acetate and ammonium

*) but if you insist on writing NH4OH, you'll get:

CH3COOH + NH4OH <--> CH3COO- + NH4+ + H2O

Answer 4

Okay, first, the ammonia dissolves in any water present to make ammonium hydroxide, which is NH4OH. So then, the two react to form ammonium acetate and more water. It's a neutralization reaction, and here's the equation:

HC2H3O2 + NH4OH --> NH4C2H3O2 + H2O

Answer 5

The reaction between acetic acid (CH3COOH) and NH4OH (ammonium hydroxide) is an acid-base reaction. The acetic acid will donate a proton (H+) to the NH4OH, forming ammonium acetate (CH3COONH4) and water (H2O). The balanced equation for the reaction is: CH3COOH + NH4OH → CH3COONH4 + H2O.

Answer 6

Ammonium acetate