Using the Ideal Gas Law,
PV = nRT
Solve for n.
n = PV/RT = (101.325 kPa)(0.050 L)/(8.314)(323K) = 0.001886575 mol
Now we know the number of moles of the gas at 50 degrees Celsius (323 Kelvin).
What we need to do now is to solve for the volume at 80 degrees Celsius (353 Kelvin).
V = nRT/P = (0.001886575 mol)(8.314)(353K)/(101.325 kPa) = 0.546 mol
Can you please tell me if this is correct?
Using Charle's law, which involves temperature and volume is V1/T1=V2/T2. To find the final temperature (T2), rewrite the equation to solve for T2.
So T2=T1*V2/V1
Now you can plug everything into the equation and solve. Just don't forget that you need to change 25 degrees Celsius to Kelvin first. (Kelvin = Celsius + 273)
T2=25 + 273 * (450mL/158mL) equals 849 Kelvin. To change back to Celsius,
849-273 = 576 degrees Celsius
Hey Candi Keller, the answer is 26.3 mL :)
Hey Candi Keller its Connor Hahaha
If it is held in a container, then it will stay as 25.3 L, but the pressure will increase.
In a sealed container the volume remain the same and the pressure increase.
26.3 mL
Dnejrnrn
Ghh
If the temperature increases, then the volume of the gases cannot stay the same. The pressure will keep building until it overcomes the integrity of the container its contained in and causes an explosion.
They're proportional; as temperature increases volume increases.
Pressure increases. yup
Universal Gas Law: P*V/T = a constant, where P = gas pressure [Pa], V = volume [m3], and T = gas temperature [K]. Therefore, when the gas temperature increases, the pressure increases linearly with it, when the volume is constant.
Assuming constant amount of gas and temperature, pressure will increase as volume decreases. Conversely, pressure will decrease as volume increases. If you squeeze on a filled balloon, the volume decreases. The pressure of the air on each square inch of the balloon increases, which causes it to eventually pop if the pressure gets too high. Assuming constant amount of gas, a temperature change will already change the volume of the gas. As temperature rises, the gas expands, causing more pressure to be exerted on the balloon. Assuming constant temperature, adding more gas also increases the volume and thus increases the pressure.
Because the pressure increases The real answer is: Charles's Law. He found that if you increase the temperature of a constant pressure the volume increases also.
Temperature increases as pressure increases.
it increases
As pressure increases, if temperature is constant, the gas will decrease in volume.
As pressure increases, if temperature is constant, the gas will decrease in volume.
The pressure increases. Hopefully, the container is strong enough to withstand the increased pressure. If there is a weakness in the container, gas will escape as a leak.
If the temperature increases, then the volume of the gases cannot stay the same. The pressure will keep building until it overcomes the integrity of the container its contained in and causes an explosion.
Use Boyle's Law, applicable for ideal gases at constant temperature, to solve this problem: P1*V1 = P2*V2
Pressure increases. yup
They're proportional; as temperature increases volume increases.
They're proportional; as temperature increases volume increases.
They're proportional; as temperature increases volume increases.