how to draw a 105 degree angle
this is an elaboration to what the previous user said: a v-shaped molecule that has a 105 degree angle is called a bent/angular molecule. It is a modified version of the tetrahedral because it has two lone pairs and two bonds around the central atom instead of the typical tetrahedron which has 4 bonds. an example of a bent molecule would be water (H20) the oxygen has 2 lone pairs and two bonds, slightly bending the shape of the molecule from linear (180) to angular (around 105). This happens because the oxygen is a little more negative (delta negative) than the hydrogens, and so the oxygen's electrons pushes themselves away from the hydrogens, creating a more bent shape (use the VSEPR theory to determine molecular shape for the future)
hope this helps!!
tip: to find the shape of a molecule, ignore the atoms involved, just focus on the electron pairs surrounding the central atom. if it has 4 bonds, it is tetrahedral, if it has one bond, it is linear, 2 bonds is also linear (JUST 2 BONDS AND NOTHING ELSE), and three bonds is trigonal planar.
those were just dealing with bonds, if there are lone pairs around the central atom as well, this is how you would deal with it: 2 bonds and 2 lone pairs is bent; 3 bonds and one lone pair is pyramidal, and one bond and 3 lone pairs is linear, (if the molecule has only one bond, it will always be linear, no matter how many lone pairs)
I know this was a lot i just wrote down whatever was on my mind haha.. but these ideas helped me out on my chem test dealing with covalent bond and shapes, hopefully it'll help u too
The angle between the bonds of a water molecule is approximately 104.5 degrees. This angle is due to the molecular geometry of water, which is bent or V-shaped.
The bond angle of a bent molecule is typically around 104.5 degrees. This angle is a result of the repulsion between the lone pairs and bonded pairs of electrons around the central atom, causing the molecule to adopt a bent shape.
The melting point of fructose is approximately 103-105 degrees Celsius.
The bond angle in silicon disulfide (SiS2) is approximately 105 degrees, and the molecular shape is bent/angular.
Yes it is bent, with 105 degree bond angle
A 75 degree angle.
obtuse angle
with compass.........at 90+60degree angle,,,,,,,,, * * * * * and 90 + 60 = 105??? You need to draw a 90 degree ange and bisect it to give a 45 deg angle. Then add a 60 degree angle. 45 + 60 = 105.
Yes
A pair of supplementary angles add up to 180 degrees. Therefore, the supplement to a 105 degree angle is equal to 180 - 105 = 75 degrees.
105 degrees
.105
An angle is supplementary to another if their measures add up to 180 degrees. To find the angle that is supplementary to a 75-degree angle, subtract 75 from 180. Therefore, 180 - 75 = 105 degrees. Thus, the angle that is supplementary to a 75-degree angle is 105 degrees.
With a protractor and a straight edge
The supplement of a 75-degree angle is the angle that, when added to 75 degrees, equals 180 degrees (a straight line). To find the supplement of a given angle, you subtract the given angle from 180 degrees. Therefore, the supplement of a 75-degree angle is 105 degrees.
Easiest is to use a protractor. Alternative: Draw a 90 degree angle. Bisect the external angle so that it is 45 degrees. Trisect that angle so that the angle adjacent to the 90 degree angle is 15 deg Then 90 + 15 degrees = 105 degrees. Both, bisection and trisection require the use of a compass (and ruler).
Half 3