For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
Its 0
Yes, the equation obeys the law of conservation of matter. The number of atoms for each element is the same on both sides of the equation, indicating that no atoms are created or destroyed during the reaction.
The oxidation half-reaction is: Fe => Fe+3 + 3e-, and the reduction half-reaction is: F2 + 2e- => 2 F-1. For a complete equation, the oxidation half-reaction as written must be multiplied by 2 and added to the reduction half-reaction as written multiplied by 3 to result in an overall reaction of 2 Fe + 3 F2 = 2 FeF3.
3H2(g) + N2(g) ---> 2NH3(g)
Based on the ideal gas law at STP (standard temperature and pressure), the volume occupied by 3.00 mmol of H2 gas would be 67.2 mL (Choice B). This calculation is done using the equation V = nRT/P, where R is the gas constant, T is the temperature, P is the pressure, n is the number of moles, and V is the volume.
Keq = [H2O][CO] [H2][CO2]
Its 0
HI will be consumed. The reaction will proceed to the left. More I2 will form.
The correct form for the equilibrium constant expression for this reaction is Kc = [HF]^2 / ([H2] * [F2]), where the square brackets denote molar concentrations of each species at equilibrium.
In the reaction ( \text{Mg} + 2 \text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2 + \text{H}_2 ), the oxidation state of each hydrogen atom in ( \text{H}_2 ) (denoted as ( \text{H}_2(g) )) is 0. This is because in diatomic molecules like ( \text{H}_2 ), the atoms are in their elemental form, and their oxidation state is defined as zero.
The reaction 2Na(s) + 2H2O(l) → 2NaOH(s) + H2(g) is a single displacement reaction, where sodium (Na) displaces hydrogen from water (H2O). This is also an exothermic reaction, as it releases energy in the form of heat when sodium reacts with water. The reaction produces sodium hydroxide (NaOH) and hydrogen gas (H2).
The reaction represented by H₂O → H₂(g) + O₂(g) is a decomposition reaction. In this reaction, water (H₂O) is broken down into its constituent elements, hydrogen gas (H₂) and oxygen gas (O₂), typically through the process of electrolysis or thermolysis. Decomposition reactions involve the separation of a compound into simpler substances.
The equilibrium constant, K_eq, for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) is equal to the concentration of H2 and Cl2 divided by the concentration of HCl squared, as products are in the numerator and reactants in the denominator.
In:(H2)g oxidation state: 0 In:(O2)g oxidation state: 0 In:(H2O)l oxidation state: H: +1 and O: -2
Yes, the equation obeys the law of conservation of matter. The number of atoms for each element is the same on both sides of the equation, indicating that no atoms are created or destroyed during the reaction.
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