Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
ka=[H+][CN-]/[HCN]
Ka= [h+][HCO3-]/[H2CO3]
The Ka for the dissociation of HNO2 is 4.5 x 10^-4. This value represents the equilibrium constant for the reaction of HNO2 dissociating into H+ and NO2-.
not sure
Ka= [H+][NO2-] [HNO2]
ka=[H+][NO2_]/[HNO2]
ka=[H+][CN-]/[HCN]
Ka= [h+][HCO3-]/[H2CO3]
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
The Ka for the dissociation of HNO2 is 4.5 x 10^-4. This value represents the equilibrium constant for the reaction of HNO2 dissociating into H+ and NO2-.
not sure
Ka= [H+][NO2-] [HNO2]
Since H3PO4 has 3 ionizable hydrogens, it will have three Ka values. Approximate values areKa1 = 7x10^-3; Ka2 = 6x10^-8 and Ka3 = 4.5x10^-13
The acid dissociation constant (Ka) for carbonic acid (H₂CO₃) dissociating into hydrogen ions (H⁺) and bicarbonate ions (HCO₃⁻) is a measure of the strength of the acid in solution. The dissociation reaction can be represented as: H₂CO₃ (aq) ⇌ H⁺ (aq) + HCO₃⁻ (aq). The value of Ka for this process is approximately 4.3 x 10⁻⁷ at 25°C, indicating that H₂CO₃ is a weak acid.
putang ina mo gaguu ka wag ka na secreto lang 2
just say gago ka gm
3.4 * 10^-8