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The latent heat of vaporization of water is 2260 joules per kilogram.

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What is the heat of vaporization of water in joules per kilogram?

The heat of vaporization of water is 2260 joules per kilogram.


A sample of H20 with a mass of 46.0 grams has a temperature of 100 c How many joules of energy are necessary to boil the water?

The heat of vaporization is about 2258 joules/gram46 x 2258 = 103,868 J ~ 103.9 kJ(Using the rounded value 2260 joules per gram, about 104 kJ)it is already at boiling point so in theory zero energy is required.I think the question is asking what energy is required to free the water from its liquid state to the vapour state.At 101325Pa, (1 atmosphere in old money), the latent heat of evaporation of water is 2256.7 J/g.So 2256.7 * 46 = 103808 Joules


How many joules of heat are needed to completely vaporize 24.40 grams of water at its boiling point?

The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.


Which process requires water to gain 2260 Joulesof energy per gram?

The process of vaporization, where water changes from liquid to gas, requires 2260 Joules of energy per gram to occur.


How much energy is required to vaporize 2kg of water at 100c?

Oh, dude, to vaporize 2kg of water at 100°C, you'd need about 2260 kilojoules of energy. It's like making a really intense cup of tea, but instead of sipping it, you're just turning it into steam. So, yeah, it's a pretty hot process, literally.

Related Questions

What is the heat of vaporization of water in joules per kilogram?

The heat of vaporization of water is 2260 joules per kilogram.


How much energy is transfered when 1gm of boiling water at 100c condenses to water at 100c?

When 1 gram of boiling water at 100°C condenses to water at the same temperature, it releases energy in the form of latent heat of vaporization. The latent heat of vaporization for water is approximately 2260 joules per gram. Therefore, when 1 gram of steam condenses, about 2260 joules of energy is transferred to the surroundings.


What step changes liquid water to water vapor?

Vaporization is the change of liquid water to water vapor. Vaporization requires addition of the latent heat of vaporization to liquid water. The latent heat of vaporization supplies the liquid water molecules with enough energy to become vapor molecules. The latent heat of vaporization at 1.0 atmosphere pressure is about 1000 Btu per lbm ( 2260 kJ per kg ).


How much energy is required to evaporate all the water on Earth?

To evaporate all the water on Earth, approximately 1.2 x 10^21 joules of energy is required. This estimate is based on Earth's total water volume of about 1.386 billion cubic kilometers and the latent heat of vaporization of water, which is around 2.26 million joules per kilogram. This immense amount of energy highlights the significant role water plays in Earth's climate and energy balance.


When water vapor condenses how much heat is released into the atmosphere?

When water vapor condenses, it releases the latent heat of vaporization, which is around 2260 joules per gram. This heat energy warms the surrounding air as it is released during the condensation process.


How your body cooled when you perspire?

Perspiration coats the outside of the skin with moisture (water). The water evaporates. Evaporation requires heat to be absorbed by the water (the latent heat of vaporization). Heat is removed from the body surface to provide the water with the latent heat of vaporization.


How many calories of heat is released when one gram of water vapor condenses into liquid water?

When one gram of water vapor condenses into liquid water, it releases about 2260 joules (540 calories) of heat energy. This process is called the latent heat of vaporization.


How many joules of energy are removed from 1 gram of water during condensation?

During condensation, approximately 2260 joules of energy are removed from 1 gram of water. This value represents the latent heat of vaporization, which is the energy required to convert water from a liquid to a gas. When water vapor condenses back into liquid water, this amount of energy is released into the surroundings.


What is the specific heat of water in joules per kilogram degree Celsius?

The specific heat of water is 4186 joules per kilogram degree Celsius.


How much heat in joules is released when 1000 g of steam at 100 C condenses to water at the same temperature?

To calculate the heat released when 1000 g of steam at 100°C condenses to water at the same temperature, we use the latent heat of vaporization for water, which is approximately 2260 J/g. Therefore, the heat released can be calculated as follows: Heat released = mass × latent heat of vaporization = 1000 g × 2260 J/g = 2,260,000 J. Thus, 2,260,000 joules of heat is released during the condensation process.


What requires more energy the latent heat vaporisation of water or the latent fusion of ice?

The latent heat of vaporisation of water requires more energy. This is because on melting, the intermolecular bonds in water are only weakened whereas on boiling, the bonds are completely broken, which requires a larger amount of energy.


A sample of H20 with a mass of 46.0 grams has a temperature of 100 c How many joules of energy are necessary to boil the water?

The heat of vaporization is about 2258 joules/gram46 x 2258 = 103,868 J ~ 103.9 kJ(Using the rounded value 2260 joules per gram, about 104 kJ)it is already at boiling point so in theory zero energy is required.I think the question is asking what energy is required to free the water from its liquid state to the vapour state.At 101325Pa, (1 atmosphere in old money), the latent heat of evaporation of water is 2256.7 J/g.So 2256.7 * 46 = 103808 Joules