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The reaction involving NaNH2 and NH3 is a nucleophilic substitution reaction. In this reaction, the NaNH2 acts as a strong base and replaces a hydrogen atom in NH3, forming a new compound. This reaction is commonly used in organic synthesis to introduce new functional groups into molecules.

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5mo ago

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What is the reaction of methanol with sodamide?

The reaction of methanol with sodamide (NaNH2) typically results in the formation of sodium methoxide (NaOCH3) and ammonia (NH3) as byproducts. This reaction is often used for the synthesis of sodium alkoxides.


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NaNH2 is a base because it can accept a proton (H+) from an acid to form ammonia (NH3) and the conjugate base of the acid. This reaction results in the formation of NH4+ and N3- ions, showing the ability of NaNH2 to accept protons and act as a base.


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According to wikipedia, the formula is: 2 Na + 2 NH3 → 2 NaNH2 + H2 I hope I helped! ;)


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