To calculate the mass in grams of each sample, you can use a balance or scale to measure the weight of the sample. The weight measured in grams is equivalent to the mass of the sample.
To determine the empirical formula, first calculate the moles of each element present by dividing the given masses by their respective molar masses. Then, divide each mole value by the smallest mole value obtained. Finally, round the resulting ratio to the nearest whole number to determine the subscripts required for the empirical formula. In this case, the empirical formula would be K2O2Sn.
To calculate the empirical formula from mass percentages, first convert the mass percentages to grams. Then divide the grams of each element by its molar mass to find the moles of each element. Finally, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio, which represents the empirical formula.
first we need calculate or research the molar mass of ASA it turns out to be 180.170 g/mol with the molecular formula C9H8O4 so to figure out the mass of each of the elements we find the precent composition; the mass of each of the elements over the mass of the entire molecule then we multiply that by the mass of the sample to give us our real world answer. C = 9(12.01) / 180.170 =.5999 * 3.000 = 1.800 grams Carbon H = 8(1.01) / 180.170 = .0448 * 3.000 = 0.1340 grams Hydrogen O = 4(16.00) /180.17 = .3553 * 3.000 = 1.066 grams Oxygen and in total 1.800 + .1340 + 1.066 = 3.000 grams ASA
Since each molecule of sodium chloride contains one sodium atom, the mass of the sodium in a 150 gram sample of sodium chloride would be the same as the mass of the sample itself, which is 150 grams.
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
1 mol of Si contains 6.02 x 1023 atoms (avogadro constant). Amount of Si = (9.99x1052) / (6.02x1023) = 3.75mol Molecular mass of Si is 28.1. Mass of Si = 3.75 x 28.1 = 105g
Random sampling is a method of selecting a sample where each member of the population has the same probability of being included in the sample. An equivalent statement is that each subset of the population, of the given size, has the same probability of being selected as any other subset of that size.
To conduct a study using the 5/8 method, researchers divide a sample into five equal groups and randomly select 8 participants from each group. This method helps ensure a representative sample for research purposes.
Stratified
A simple random sample is a method of selecting a sample where the probability of any particular member of the population being part of the sample is the same for all members of the population.
To calculate rainfall using the Thiessen polygon method, you first need to divide the area into polygons based on rain gauge locations. Then, calculate the area of influence of each rain gauge within its polygon. Finally, you can determine the weight of each rain gauge based on its influence area, which is used to calculate the average rainfall for the entire region.
simple random sample is to select the sample in random method but systematic random sample is to select the sample in particular sequence (ie 1st 11th 21st 31st etc.)• Simple random sample requires that each individual is separately selected but systematic random sample does not selected separately.• In simple random sampling, for each k, each sample of size k has equal probability of being selected as a sample but it is not so in systematic random sampling.
Silver has a density of approximately 10.49 g/cm³, while lead has a density of about 11.34 g/cm³. Since both samples have the same volume of 1 cm³, the lead sample would have a greater mass than the silver sample. The mass of the lead sample would be about 11.34 grams, while the mass of the silver sample would be about 10.49 grams, resulting in a difference of approximately 0.85 grams.
The number of Cadbury Mini Eggs in 100 grams can vary slightly due to their size and weight variations, but there are typically around 20 to 25 Mini Eggs in that amount. Each Mini Egg weighs approximately 4 to 5 grams. For a more precise count, it's best to weigh a sample and calculate based on that.
To determine the empirical formula, first calculate the moles of each element present by dividing the given masses by their respective molar masses. Then, divide each mole value by the smallest mole value obtained. Finally, round the resulting ratio to the nearest whole number to determine the subscripts required for the empirical formula. In this case, the empirical formula would be K2O2Sn.
Silver has a density of approximately 10.49 g/cm³, while lead has a density of about 11.34 g/cm³. Therefore, the lead sample, with a volume of 1 cm³, would have a greater mass than the silver sample. Specifically, the mass of the silver would be about 10.49 grams, while the mass of the lead would be around 11.34 grams, resulting in a difference of approximately 0.85 grams.