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How To Determine The Empirical Formula From 46.25 grams Sample That Contains 14.77 grams Of K 9.06 Of O 22.42 grams Of tin.?
To determine the empirical formula, first calculate the moles of each element present by dividing the given masses by their respective molar masses. Then, divide each mole value by the smallest mole value obtained. Finally, round the resulting ratio to the nearest whole number to determine the subscripts required for the empirical formula. In this case, the empirical formula would be K2O2Sn.
How to calculate the empirical formula from mass percentages?
To calculate the empirical formula from mass percentages, first convert the mass percentages to grams. Then divide the grams of each element by its molar mass to find the moles of each element. Finally, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio, which represents the empirical formula.
What is the mass in gram of each component in acetylsalicylic acid hydrogen carbon and oxygen in 3.000 g sample?
first we need calculate or research the molar mass of ASA it turns out to be 180.170 g/mol with the molecular formula C9H8O4 so to figure out the mass of each of the elements we find the precent composition; the mass of each of the elements over the mass of the entire molecule then we multiply that by the mass of the sample to give us our real world answer. C = 9(12.01) / 180.170 =.5999 * 3.000 = 1.800 grams Carbon H = 8(1.01) / 180.170 = .0448 * 3.000 = 0.1340 grams Hydrogen O = 4(16.00) /180.17 = .3553 * 3.000 = 1.066 grams Oxygen and in total 1.800 + .1340 + 1.066 = 3.000 grams ASA
What mass of sodium would make up a 150 gram sample of sodium chloride?
Since each molecule of sodium chloride contains one sodium atom, the mass of the sodium in a 150 gram sample of sodium chloride would be the same as the mass of the sample itself, which is 150 grams.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
How many grams of silicon would there be in a sample that contained 9.991052 atoms?
1 mol of Si contains 6.02 x 1023 atoms (avogadro constant). Amount of Si = (9.99x1052) / (6.02x1023) = 3.75mol Molecular mass of Si is 28.1. Mass of Si = 3.75 x 28.1 = 105g
What is the random sampling method?
Random sampling is a method of selecting a sample where each member of the population has the same probability of being included in the sample. An equivalent statement is that each subset of the population, of the given size, has the same probability of being selected as any other subset of that size.
How to conduct a study using the 5/8 method?
To conduct a study using the 5/8 method, researchers divide a sample into five equal groups and randomly select 8 participants from each group. This method helps ensure a representative sample for research purposes.
Which sampliing method subdivides the population into categories sharing similar characteristics and then selects a sample from each subdivision?
Stratified
What is the meaning of ramdom sample?
A simple random sample is a method of selecting a sample where the probability of any particular member of the population being part of the sample is the same for all members of the population.
How do you calculate rainfall using the thiessen polygon method?
To calculate rainfall using the Thiessen polygon method, you first need to divide the area into polygons based on rain gauge locations. Then, calculate the area of influence of each rain gauge within its polygon. Finally, you can determine the weight of each rain gauge based on its influence area, which is used to calculate the average rainfall for the entire region.
What is the difference between simple random sampling and systematic random sampling?
simple random sample is to select the sample in random method but systematic random sample is to select the sample in particular sequence (ie 1st 11th 21st 31st etc.)• Simple random sample requires that each individual is separately selected but systematic random sample does not selected separately.• In simple random sampling, for each k, each sample of size k has equal probability of being selected as a sample but it is not so in systematic random sampling.
How To Determine The Empirical Formula From 46.25 grams Sample That Contains 14.77 grams Of K 9.06 Of O 22.42 grams Of tin.?
To determine the empirical formula, first calculate the moles of each element present by dividing the given masses by their respective molar masses. Then, divide each mole value by the smallest mole value obtained. Finally, round the resulting ratio to the nearest whole number to determine the subscripts required for the empirical formula. In this case, the empirical formula would be K2O2Sn.
How to calculate the empirical formula from mass percentages?
To calculate the empirical formula from mass percentages, first convert the mass percentages to grams. Then divide the grams of each element by its molar mass to find the moles of each element. Finally, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio, which represents the empirical formula.
How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?
46 calories (or 192, 464 joules) for each Celsius degree.
What is the mass in gram of each component in acetylsalicylic acid hydrogen carbon and oxygen in 3.000 g sample?
first we need calculate or research the molar mass of ASA it turns out to be 180.170 g/mol with the molecular formula C9H8O4 so to figure out the mass of each of the elements we find the precent composition; the mass of each of the elements over the mass of the entire molecule then we multiply that by the mass of the sample to give us our real world answer. C = 9(12.01) / 180.170 =.5999 * 3.000 = 1.800 grams Carbon H = 8(1.01) / 180.170 = .0448 * 3.000 = 0.1340 grams Hydrogen O = 4(16.00) /180.17 = .3553 * 3.000 = 1.066 grams Oxygen and in total 1.800 + .1340 + 1.066 = 3.000 grams ASA
A sample of Se weighs 20.5 grams will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams?
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
