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What is the molecular weight of air in lb/lbmol?
The molecular weight of air is approximately 28.97 lb/lbmol.
What is the molecular weight of water in lb/lbmol?
The molecular weight of water is 18 lb/lbmol.
What is the molar mass of water in lb/lbmol?
The molar mass of water is approximately 18.015 lb/lbmol.
How much 66 baume sulfuric acid is required to neutralize 350lbs of sodium hydroxide?
66 Baume Sulfuric Acid is contains 93.2% H2SO4 by weight in water. It requires 1 lbmol of H2SO4 to neutralize 2 lbmol of NaOH. Assuming that 350 lbs of NaOH is pure, there are 8.75 lbmol of NaOH. (Divide 350lb by 40 lb/lbmol, the MW of NaOH.) It takes 4.375 lbmol of H2SO4 to neutralize the 350 lb of NaOH because there are 2 lbmol of H per lbmol of H2SO4 and one lbmol of OH per lbmol of NaOH. 4.375 lbmol is equivalent to 428.75 lb of H2SO4. (Multiply by 98 lb/lbmol, the MW of H2SO4.) Then divide by 93.2% or 0.932 to get the quanty of 66 Baume containing 428.75 lb of H2SO4. 460 lb of 66 Baume. The density of 66 Baume is 1.8354 g/cm3 which is equivalent to 15.32 lb/gallon. (Mulitply by 8.345.) Finally, it requires 30 gallons of 66 baume to neutralize 350 lbs of NaOH. (Divide 460 by 15.32.)
How many lb-moles of substance are present in the given sample?
To determine the number of lb-moles in a sample, divide the weight of the sample in pounds by the molecular weight of the substance. This will give you the number of lb-moles present in the sample.
What is the molecular weight of air in lb/lbmol?
The molecular weight of air is approximately 28.97 lb/lbmol.
What is the molecular weight of water in lb/lbmol?
The molecular weight of water is 18 lb/lbmol.
What is the molar mass of water in lb/lbmol?
The molar mass of water is approximately 18.015 lb/lbmol.
How much 66 baume sulfuric acid is required to neutralize 350lbs of sodium hydroxide?
66 Baume Sulfuric Acid is contains 93.2% H2SO4 by weight in water. It requires 1 lbmol of H2SO4 to neutralize 2 lbmol of NaOH. Assuming that 350 lbs of NaOH is pure, there are 8.75 lbmol of NaOH. (Divide 350lb by 40 lb/lbmol, the MW of NaOH.) It takes 4.375 lbmol of H2SO4 to neutralize the 350 lb of NaOH because there are 2 lbmol of H per lbmol of H2SO4 and one lbmol of OH per lbmol of NaOH. 4.375 lbmol is equivalent to 428.75 lb of H2SO4. (Multiply by 98 lb/lbmol, the MW of H2SO4.) Then divide by 93.2% or 0.932 to get the quanty of 66 Baume containing 428.75 lb of H2SO4. 460 lb of 66 Baume. The density of 66 Baume is 1.8354 g/cm3 which is equivalent to 15.32 lb/gallon. (Mulitply by 8.345.) Finally, it requires 30 gallons of 66 baume to neutralize 350 lbs of NaOH. (Divide 460 by 15.32.)
How many lb-moles of substance are present in the given sample?
To determine the number of lb-moles in a sample, divide the weight of the sample in pounds by the molecular weight of the substance. This will give you the number of lb-moles present in the sample.
Weight of air?
The weight of a tube of air as high as the Earth's entire atmosphereis 14.6 lb per square inch at the bottom of the tube.
100 lb of wet air contain 0.10lb water per lb of dry air is mixed with 50 lb another wet air contain 0.02 lb water per lb of dry air calculate the lb of water per lb of dry air in final mixture?
Find the total weight of the water and divide by the total about of air. ((100lb air X .10lb water) + (50lb air x .02lb water)) Divided by (100lb air + 50lb air)=.073lb water per lb of air
How do you convert BTU per lb to BTU per scf?
Btu / scf = Btu / lb X MW / 379.5 where: MW = molecular weight of the gas, lb / lb-mol The constant 379.5 is the molar volume at standard conditions of 14.696 psia and 60°F
What does lb for lb mean in boxing?
It refers to their weight lb for lb or pound for pound
Estimate the total weight of two boxes that weight 9.4 lb and 62.6 lb using rounding and compatible numbers which estimate is closer to the actual total weight why?
Rounding the weights to 10 lb and 60 lb gives an estimated total weight of 70 lb. Using compatible numbers by rounding to 9 lb and 60 lb, the estimated total weight is 69 lb. The estimate using compatible numbers (69 lb) is closer to the actual total weight of 71.6 lb.
What is Gross weight of 30 lb of freon and container?
The gross weight of 30 lb of Freon and its container depends on the weight of the container. If we assume the container weighs 2 lb, then the total gross weight would be 32 lb.
How much air volume is needed to float 1000 pounds?
To determine the volume of air needed to float an object, you need to know the density of air and the weight of the object. For example, if the density of air is approximately 0.075 lb/ft³, then to float a 1000-pound object, you would need approximately 13,333.33 ft³ of air (1000 lb / 0.075 lb/ft³ = 13,333.33 ft³).
