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A covalent bond is present in HF. This bond is formed by sharing electrons between the hydrogen and fluorine atoms.

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1y ago

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Is HF a weak bond?

Hydrogen fluoride (HF) forms a strong bond due to the high electronegativity difference between hydrogen and fluorine. The bond is highly polarized, making it strong compared to other hydrogen halides. So, HF is not considered a weak bond.


Are the polar bonds present in HF?

Yes, a polar bond is present in HF because fluorine is more electronegative than hydrogen, leading to an unequal sharing of electrons and a partial negative charge on fluorine and a partial positive charge on hydrogen.


What kind of bond is not present in a saturated fat but is in a unsaturated fat?

c=c bond is present in saturated and c-c bond is present in unsaturated


Is solid silver a metallic bond if not what kind of bond is it?

Metallic bond is present in silver (metal).


Does hf form hydrogen bond?

Yes, it can.


Does HF have a polar covalent bond?

yes it is a polar covalent bond. the difference of electronegativities of H and F is 1.9 , it should be an ionic bond but the ratio of atomic sizes of both the atoms is responsible for polar covalent bond.


What covalent bond is most polar?

A good candidate would be the bond in HF.


What molecules contains a covalent bond HF CN- LiCl MgO?

HF and CN- have covalent bonds.


Which of the following molecules has a polar covalent bond iron oxide (Fe2O3) potassium chloride (KCl) bromine gas (Br2) hydrogen fluoride (HF)?

HF has a polar covalent bond.


What type of bond is formed between the two atoms in the compound HF?

Covalent. The bond is polar due to the high electronegativity of fluorine.


What type of bonding HF is?

HF has a polar covalent bond. The electronegativity difference between hydrogen and fluorine causes the electrons to be unequally shared, leading to a polar bond where fluorine is partially negative and hydrogen is partially positive.


Compare the strength of hydrogen bond in HF HCl HBr HI?

HF > HCl > HBr > HI Hydrogen-bond strength is determined by the electronegativity difference; since fluorine has the smallest radius, it exerts the greatest attractive force over the H+ cation, creating the strongest bond.