Delta G is the change in Gibbs free energy. Gibbs Free energy is defined as:-
G= H-TS
at constant temperature
so the factors ar the change in enthalpy (H) and entropy (S)
Delta G (written triangle G) = Delta H -T Delta S
If delta G is negative, then K (Upper case K, as in Keq or the equilibrium constant) will be greater than 1. Remember that delta G = -RT log K.Do not get Keq confused with lower case k, which denotes rate constants (which have NOTHING TO DO WITH Keq or delta G).
The change in enthalpy between products and reactants in a reaction
At the melting point, the solid and liquid phases are in equilibrium so the value of delta G is zero.
As spontaneous
enzymes dont affect the delta G, they only lower the activation energy. Therefore, the delta G stays the same
Delta G (written triangle G) = Delta H -T Delta S
Delta G (written triangle G) = Delta H -T Delta S
Delta G (written triangle G) = Delta H -T Delta S
When a chemical reaction has a negative delta G, the reaction is exothermic because delta G is the change in energy of a system and the change in its entropy. If the effect of a reaction is to reduce G, the process will be spontaneous so delta G is negative. Hope this helps :)
G is always positive when enthalpy increases and entropy decreases.
The magnitude of friction is proportional to the magnitude of the normal force which is proportional to the magnitude of gravity(The magnitude of the normal force is indirectly proportional to the magnitude of gravity.). The magnitude of the normal force, N, compared to gravity, G, on angle z, is: N=cos(z)*G On a flat surface. N=G The coefficient of friction, whether static or kinetic, f is therefore: N=cos(z)*G*f
Photosynthesis is a positive delta G as it produces more free energy than it uses. The overall result of the Gibbs equations shows that delta G is positive
The change in enthalpy between products and reactants in a reaction
No. The order of adding vectors does not affect the magnitude or direction. of the result.
If delta G is negative, then K (Upper case K, as in Keq or the equilibrium constant) will be greater than 1. Remember that delta G = -RT log K.Do not get Keq confused with lower case k, which denotes rate constants (which have NOTHING TO DO WITH Keq or delta G).
the absolute value of displacement which is delta equals x2-x1