What are the bond angles of PF3Br2?

Answer 1

The central atom of a phosphorus pentafluoride molecule is the phosphorus atom. Five fluorine atoms are directly bonded to it and there is no lone pairs located in the central atom. Having a trigonal bipyramidal shape, every bond angle in the equatorial plane is equal to 120 degrees and every bond angle in axial plane is equal to 90 degrees..

Answer 2

The bond angles of PF3Br2 are approximately 90 degrees. This is because phosphorus pentahalides (PF5, PF3Br2) tend to have bond angles close to 90 degrees due to the presence of lone pairs on the central phosphorus atom, which repel the bonding pairs, resulting in a slightly distorted trigonal bipyramidal geometry.

Answer 3

According to (see links) a microwave measurement in 1949 obtained the P-F bond length to be 1.535 Å (or 0.1535nm). If PF3 act as a ligand this number will change a bit.

Answer 4

PF3 is a pyramidal molecule just like NH3.

Answer 5

F-P-F: 120

Br-P-Br: 180

F-P-Br: 90