Oxygen can have oxidation states of -2 (in most compounds), -1 (in peroxides), 0 (in O2), +1 (in superoxides), and +2 (in compounds like OF2).
Nitrogen and oxygen are both nonmetals that can form a variety of polyatomic ions and molecules with multiple oxidation states. Nitrogen can form compounds with different oxidation states ranging from -3 to +5, while oxygen can form compounds with oxidation states ranging from -2 to -1.
Oxygen can have oxidation states of -2, 0, +1/2, or -1. The most common oxidation state of oxygen is -2, such as in water (H2O) and carbon dioxide (CO2).
Oxygen can have oxidation states of -2, -1, 0, 1, 2 in chemical compounds.
Metals that exhibit multiple oxidation states can have different levels of positive charge, known as oxidation states. These can vary depending on the compound the metal is in. For example, iron can have oxidation states of 2 and 3.
the answer is -2.Related Information:The oxidation number of oxygen when it appears as an element is 0. The oxidation number in all compounds but peroxides is -2. The oxidation number of oxygen in peroxides is -1.
Nitrogen and oxygen are both nonmetals that can form a variety of polyatomic ions and molecules with multiple oxidation states. Nitrogen can form compounds with different oxidation states ranging from -3 to +5, while oxygen can form compounds with oxidation states ranging from -2 to -1.
Oxygen can have oxidation states of -2, 0, +1/2, or -1. The most common oxidation state of oxygen is -2, such as in water (H2O) and carbon dioxide (CO2).
Oxygen can have oxidation states of -2, -1, 0, 1, 2 in chemical compounds.
Metals that exhibit multiple oxidation states can have different levels of positive charge, known as oxidation states. These can vary depending on the compound the metal is in. For example, iron can have oxidation states of 2 and 3.
the answer is -2.Related Information:The oxidation number of oxygen when it appears as an element is 0. The oxidation number in all compounds but peroxides is -2. The oxidation number of oxygen in peroxides is -1.
The oxidation number of an element depend on another element it react with to form a compound e.g manganese(iv)oxide mno4 the oxidation number of oxygen there is four while the oxidation number of manganse is 7 in most radox reaction the oxidation number of oxygen is usually 4 when writing the full equation
In a diatomic gas, such as O₂ or N₂, the oxidation states of the atoms are typically zero. This is because the atoms are in their elemental form and are not combined with different elements, which would give them positive or negative oxidation states. For example, in the case of O₂, each oxygen atom has an oxidation state of 0. Similarly, in N₂, each nitrogen atom also has an oxidation state of 0.
FClO4 is the name of Fluorine perchlorate.Here Chlorine is in +7 oxidation state, Fluorine is in -1 oxidation state, 3 atoms of Oxygen (that are double bonded to Chlorine) are in -2 oxidation state, and the forth Oxygen atom (which is connected to Fluorine and Chlorine) is in 0 oxidation state.So, total charge = 7(of Chlorine) -1(of Fluorine) -(2 * 3)(of 3 Oxygen) +0(of Fourth Oxygen) = 0
Oxygen and sulfur have similar electronegativities, so they tend to share electrons in covalent bonds. This leads to similar oxidation states for both elements in compounds. Oxygen typically has an oxidation state of -2, while sulfur usually has oxidation states of -2, +4, and +6.
The oxidation state of chromium (Cr) in Ag2Cr2O7 is +6. This is because the total charge of the compound is zero, and the oxidation states of silver (Ag) and oxygen (O) are fixed. By assigning an oxidation state of +6 to oxygen, we can determine that chromium is in the +6 oxidation state.
To find the oxidation number of chlorine, consider that chlorine typically has an oxidation number of -1 in its compounds. However, in certain situations, such as when bonded with oxygen or other halogens, chlorine can have different oxidation states. It's important to follow the usual oxidation number rules and balance the charges in the compound to determine the oxidation number of chlorine.
The sum of the oxidation states in H2SbO3 is equal to zero since the overall charge of the compound is neutral. In H2SbO3, antimony (Sb) has an oxidation state of +5, oxygen (O) has an oxidation state of -2, and hydrogen (H) has an oxidation state of +1. Summing these oxidation states gives an overall charge of zero.