The chemical formula AgNO3 represents silver nitrate. This compound consists of three elements: silver (Ag), nitrogen (N), and oxygen (O). Silver is a transition metal, nitrogen is a nonmetal, and oxygen is also a nonmetal. When these elements combine in the specific ratio in silver nitrate, they form a stable compound with distinct chemical and physical properties.
The chemical formula for silver nitrate is AgNO3.
Silver nitrate has the formula ; AgNO3'. The elements present are 1 x Silver (Ag ; Argentum ; Latin) 1 x Nitrogen (N) 3 x Oxygen (O3)
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
A compound: any formula that contains more than one kind of atomic symbols represents a compound.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
The chemical formula for silver nitrate is AgNO3.
Silver nitrate has the formula ; AgNO3'. The elements present are 1 x Silver (Ag ; Argentum ; Latin) 1 x Nitrogen (N) 3 x Oxygen (O3)
The chemical formula for silver nitrate is AgNO3.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
A compound: any formula that contains more than one kind of atomic symbols represents a compound.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
AgNO3 powder is white but a little grey solid.
The chemical formula of silver nitrate is AgNO3.
The correct formula for silver (I) nitrate is AgNO3.
Silver nitrate (AgNO3) is composed of 63.5% silver by mass.
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
When mixing NaCl and AgNO3, a chemical reaction occurs resulting in the formation of a compound called AgCl (silver chloride). AgCl is a compound, not an element, as it is made up of two different elements (silver and chlorine) chemically bonded together.