The reactants are calcium carbonate and hydrogen chloride.
The balanced equation for hydrochloric acid (HCl) reacting with calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + CO2 + H2O.
The reaction between chalk (calcium carbonate, CaCO3) and hydrochloric acid (HCl) can be represented by the chemical equation: CaCO3 + 2HCl → CaCl2 + CO2 + H2O
Limestone is predominantly calcium carbonate, CaCO3, and reacts with hydrochloric acid as follows: CaCO3(s) + 2HCl(aq) --> CaCl2(aq) + CO2(g) + H2O
The balanced chemical equation for the reaction of calcium carbonate (CaCO3) with hydrochloric acid (HCl) is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O.
The balanced equation is: 2HCl + CaCO3 -> CaCl2 + H2O + CO2
The balanced equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + H2O + CO2.
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
The balanced equation for hydrochloric acid (HCl) reacting with calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + CO2 + H2O.
The reaction between chalk (calcium carbonate, CaCO3) and hydrochloric acid (HCl) can be represented by the chemical equation: CaCO3 + 2HCl → CaCl2 + CO2 + H2O
Limestone is predominantly calcium carbonate, CaCO3, and reacts with hydrochloric acid as follows: CaCO3(s) + 2HCl(aq) --> CaCl2(aq) + CO2(g) + H2O
The balanced chemical equation for the reaction of calcium carbonate (CaCO3) with hydrochloric acid (HCl) is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O.
The balanced equation is: 2HCl + CaCO3 -> CaCl2 + H2O + CO2
Let's check it! CaOH+CO2 ---> CaHCO3 You can't do it any other way. Calcium Carbonate is CaCO3, so all that will leave is hydrogen. Depending on how you react it, you can either get calcium bicarbonate or calcium carbonate and hydrogen. If you get calcium bicarbonate, try baking it to release hydrogen.
CaCO3 + 2HCl -> CaCl2 +H2O +CO2
The chemical equation for the reaction between stomach acid (hydrochloric acid, HCl) and calcium carbonate (CaCO3) is: CaCO3(s) + 2HCl(aq) -> CaCl2(aq) + CO2(g) + H2O(l)
You can find a answer fromCalcium carbonate - Wikipedia
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).