K+ and NO3- because KOH + HNO3 (yields) H2O + KNO3
OH- 2H+ -> 2H2O(I) ywwww :)
This answer balances a theoretical reaction that does not occur in nature. 2KOH + Zn -> Zn(OH)2 + 2K Zn actually dissolves in strong base to form a so called "zincate" which was traditionally gven the formula of ZnO22- . It is now recognised that these zincate ions are hydrated to various degrees and one such ion is (Zn(OH)4)2- . Zn + 2KOHaq -> K2ZnO2aq +H2
OH- 2H+ -> 2H2O(I) ywwww :)
To write the complete ionic equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H₂SO₄), we first recognize that KOH dissociates into K⁺ and OH⁻ ions, while H₂SO₄ dissociates into 2 H⁺ and SO₄²⁻ ions. The complete ionic equation is: 2 K⁺(aq) + 2 OH⁻(aq) + 2 H⁺(aq) + SO₄²⁻(aq) → 2 H₂O(l) + K₂SO₄(aq). This shows the ions involved in the reaction and the products formed.
This answer balances a theoretical reaction that does not occur in nature. 2KOH + Zn -> Zn(OH)2 + 2K Zn actually dissolves in strong base to form a so called "zincate" which was traditionally gven the formula of ZnO22- . It is now recognised that these zincate ions are hydrated to various degrees and one such ion is (Zn(OH)4)2- . Zn + 2KOHaq -> K2ZnO2aq +H2