K+ and SO42-
In the reaction 2KOH + H2SO4 -> 2H2O + K2SO4, the spectator ions are K+ and SO4^2-. These ions do not participate in the chemical reaction i.e., they remain unchanged before and after the reaction.
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
2KHCO3(aq) + H2SO4(aq) [bidirectional arrows] K2SO4(aq) + 2CO2(g) + 2H2O(l)
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
2KOH + H2SO4 --> K2SO4 + 2H2O2KOH(aq) + H2SO4(aq) --> K2SO4(aq) + 2H2O(l)
In the reaction 2KOH + H2SO4 -> 2H2O + K2SO4, the spectator ions are K+ and SO4^2-. These ions do not participate in the chemical reaction i.e., they remain unchanged before and after the reaction.
K+ and SO42-
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
2KHCO3(aq) + H2SO4(aq) [bidirectional arrows] K2SO4(aq) + 2CO2(g) + 2H2O(l)
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
2KOH + H2SO4 --> K2SO4 + 2H2O2KOH(aq) + H2SO4(aq) --> K2SO4(aq) + 2H2O(l)
H2so4+2koh=k2so4+2h2o
H2SO4 + 2KOH = K2SO4 + 2H2O
If is K2O (potassium oxide) it would be: K2O+H2SO4=K2SO4+H2O It could also form potassium bisulfate: K2O + 2 H2SO4 = 2 KHSO4 + H2O But I'm not sure if you are referring to potassium peroxide (K2O2) or superoxide (KO2)
The net ionic equation for the reaction between 2KOH and H2SO4 to form K2SO4 and water is: 2OH- + 2H+ -> 2H2O
The products of a neutralization reaction between sulfuric acid and potassium hydroxide are potassium sulfate and water. The balanced chemical equation for this reaction is H2SO4 + 2KOH -> K2SO4 + 2H2O.
Answer this question… OH- + 2H+ 2H2O(l)