we use kcl to find out current with the help of equation ;and also we calculate the value of voltage ,kcl is the law which explaine that all the leaving current =entering current or sum of all currents at junction is zero
KCl is highly soluble in water and some other solvents.
The systematic name for KCl is potassium chloride.
A potassium chloride (KCl) solution is colorless.
There are two types of atoms in KCl, potassium (K) and chlorine (Cl). The chemical formula KCl indicates that there is one atom of potassium and one atom of chlorine in each molecule of KCl.
The remaining 10 g of KCl forms a saturated solution in water, meaning the solution is in dynamic equilibrium with solid KCl dissolving and KCl ions re-crystallizing at the same rate. The resulting solution will contain both dissolved K+ and Cl- ions in equilibrium with undissolved KCl crystals.
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
KCl is soluble in DMF
KCl is a compound not an element.
KCl is 'potassium chloride'.
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
No. Potassium chloride (KCl) is soluble in water.
KCl is highly soluble in water and some other solvents.
I'm guessing you meant KCl or potassium chloride.
Molar mass of KCl = 74.55g/mol.ie, if you dissolve 74.55g KCl in 1litre (1000 ml) of water, it will be 1M KCl solution.If you want to make 3M KCl solution,Dissolve 3 ×74.55 = 223.65g KCl in 1litre (1000 ml) of water.If you want to make different molar solutions of KCl, just calculate as per below given equation.Weight of KCl to be weighed =Molarity of the solution needed × Molecular weight of KCl (ie, 74.55) × Volume of solution needed in ml / 1000.To prepare 3M KCl in 1 litre, it can be calculated as follows,3 mol × 74.55 g/mol × 1000 ml / 1000 ml = 223.65gByPraveen P Thalichalam, Kasaragod (Dist), Kerala.
The answer is of course 0,9 M.
A potassium chloride (KCl) solution is colorless.