It has one nucleon.
It has no neutrons.
It has one proton.
When P-32 decays to S-32, a beta particle is emitted. This beta particle is an electron released during the conversion of a neutron into a proton within the nucleus of the atom.
In atomic structure, shells are energy levels where electrons are found, while subshells are smaller regions within shells where electrons with specific energy levels are located. Shells are labeled with numbers (1, 2, 3, etc.), while subshells are labeled with letters (s, p, d, f).
a bromine ion will have 36 electrons and a -1 charge
The particle is an atom of selenium (Se). It has 34 protons and 34 electrons, since the number of protons equals the number of electrons in a neutral atom. The electron configuration given ("1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6") matches that of selenium.
We usually see p+ used for the proton. Remember that it's a hydrogen nucleus. It might appear as H+ to denote a hydrogen atom (actually an ion) that has lost its electron and is a lonely proton with its characteristic +1 charge. Note that a hydrogen nucleus can sometimes have one or even two neutrons stuck together with the proton. Just so ya know. Also, it can be written as 1 over 1 p
It has one nucleon it has no neutrons it has one proton
p
, ,p,;p;
Proton.
I am assuming that this is to do with the trajectory that is simplified to that of a particle which does not incur air resistance. If I have understood the question correctly, the particle travels under the influence of a constant force - assumed to be gravity which acts downwards. The model can be extended to allow for a constant force acting at an angle but the calculations then become more complicated. The particle is projected upwards, with the initial velocity, u ms-1, which makes an angle P with the horizontal. u is a variable such that the horizontal range of the particle is a constant. The vertical component of the initial velocity is u*sin(P) ms-1. The gravitational force, acting downwards, is -g ms-2. When the particle returns to the ground level, the vertical component of its velocity is -u*sin(P) ms-1. So if the particle returns at time t seconds, then t = [u*sin(P) - -u*sin(P)] /g = 2*u*sin(P)/g sec. The horizontal component of the velocity of the particle is a constant u*cos(P) ms-1. So during the time in flight, it travels u*cos(P)*2*u*sin(P)/g m = 2*u2*sin(P)*cos(P)/g m. This horizontal distance is constant, which implies that 2*u2*sin(P)*cos(P)/g is constant so that u2 is inversely proportional to sin(P)*cos(P). So let u = sqrt[k/sin(P)*cos(P)] ms-1 for some constant k. then its vertical component is u*sin(P) = sqrt[k/sin(P)*cos(P)]*sin(P) ms-1 = sqrt[k*tan(P)] Then at time T, its height is sqrt[k*tan(P)]*T - 0.5g*T2 I just hope this is correct!
The answer is 1/90.
When P-32 decays to S-32, a beta particle is emitted. This beta particle is an electron released during the conversion of a neutron into a proton within the nucleus of the atom.
Particle
In physics, the relationship between the speed of light (c), energy (E), and momentum (p) of a particle is described by the equation E pc, where E is the energy of the particle, p is its momentum, and c is the speed of light. This equation shows that the energy of a particle is directly proportional to its momentum and the speed of light.
A proton can be written as p, p+, or by its quantum numbers: 1/2(1/2)+, corresponding to spin(isospin)parity.
The de Broglie equation can be derived by combining the principles of wave-particle duality and the equations of classical mechanics. It relates the wavelength of a particle to its momentum, and is given by h/p, where is the wavelength, h is Planck's constant, and p is the momentum of the particle.
Particle.