It has one nucleon.
It has no neutrons.
It has one proton.
It has no neutrons, it has one proton, it has one nucleon
This is the ion selenium(2-).
beta
Add up, knowing that p's are Positive and e's are nEgative: +116p(= '+') + 15e(= '-') makes (+16) + (-15) = +1So the overall charge of this 'particle' is +1(If it were a chemical particle it would have been the NON-existing S+ ion)
no. ions are made of relatively whole atoms (plus or minus a few electrons)
The sub atomic particles to an atom are the proton (p), neutron (n). The p and n both contribute to atomic mass. The positive charge comes from the p and outside the atom in orbit is/are the electron with negligible mass, but negative charge.
It has one nucleon it has no neutrons it has one proton
p
, ,p,;p;
Proton.
A proton can be written as p, p+, or by its quantum numbers: 1/2(1/2)+, corresponding to spin(isospin)parity.
I am assuming that this is to do with the trajectory that is simplified to that of a particle which does not incur air resistance. If I have understood the question correctly, the particle travels under the influence of a constant force - assumed to be gravity which acts downwards. The model can be extended to allow for a constant force acting at an angle but the calculations then become more complicated. The particle is projected upwards, with the initial velocity, u ms-1, which makes an angle P with the horizontal. u is a variable such that the horizontal range of the particle is a constant. The vertical component of the initial velocity is u*sin(P) ms-1. The gravitational force, acting downwards, is -g ms-2. When the particle returns to the ground level, the vertical component of its velocity is -u*sin(P) ms-1. So if the particle returns at time t seconds, then t = [u*sin(P) - -u*sin(P)] /g = 2*u*sin(P)/g sec. The horizontal component of the velocity of the particle is a constant u*cos(P) ms-1. So during the time in flight, it travels u*cos(P)*2*u*sin(P)/g m = 2*u2*sin(P)*cos(P)/g m. This horizontal distance is constant, which implies that 2*u2*sin(P)*cos(P)/g is constant so that u2 is inversely proportional to sin(P)*cos(P). So let u = sqrt[k/sin(P)*cos(P)] ms-1 for some constant k. then its vertical component is u*sin(P) = sqrt[k/sin(P)*cos(P)]*sin(P) ms-1 = sqrt[k*tan(P)] Then at time T, its height is sqrt[k*tan(P)]*T - 0.5g*T2 I just hope this is correct!
The answer is 1/90.
Particle
This is the ion selenium(2-).
beta
Particle velocityparticle displacementpolarizationpressureplasmas
particle