Purple to colourless
Alkenes have a double bond between the carbon atoms (C=C) whereas alkanes have a single bond (C-C). so alkenes are unsaturated compounds, add aqueous solution of Bromine or KMnO4 to both the compounds the decolourization of these reagents confirms the presence of alkenes.
Benzene cannot decolorize KMnO4 because it does not undergo addition reactions due to its stable aromatic structure. Alkenes, on the other hand, can decolorize KMnO4 because they can undergo addition reactions with KMnO4, breaking the double bond and forming a colorless product.
When ethanol reacts with excess acidified KMnO4, it is oxidized to form ethanoic acid. The purple color of KMnO4 is decolorized to colorless Mn2+ ions during the reaction.
When potassium permanganate (KMnO4) reacts with formaldehyde (HCHO), it undergoes oxidation-reduction reaction. The purple color of KMnO4 fades as it gets reduced to Mn2+ ions, while formaldehyde is oxidized to formic acid (HCOOH) or carbon dioxide and water. Heat may be evolved during the reaction.
Baeyer's test for unsaturation using KMnO4 . if the sol'n retains the purple color of the reagent , then it is an alkane. if the color disappears with formation of brown precipitate ,it indicates presence of unsaturated HC
The purple KMnO4 is decolourise
Alkenes have a double bond between the carbon atoms (C=C) whereas alkanes have a single bond (C-C). so alkenes are unsaturated compounds, add aqueous solution of Bromine or KMnO4 to both the compounds the decolourization of these reagents confirms the presence of alkenes.
Benzene cannot decolorize KMnO4 because it does not undergo addition reactions due to its stable aromatic structure. Alkenes, on the other hand, can decolorize KMnO4 because they can undergo addition reactions with KMnO4, breaking the double bond and forming a colorless product.
Alkanes cannot be oxidized by KMnO4 because they lack functional groups that can undergo oxidation reactions. KMnO4 is a strong oxidizing agent that typically reacts with compounds containing double or triple bonds, alcohols, or other oxidizable functional groups. Alkanes are saturated hydrocarbons, meaning they only contain single bonds between carbon atoms, making them relatively stable and unreactive towards oxidation. Thus, KMnO4 does not effectively oxidize alkanes under normal conditions.
Benzene does not react directly with potassium permanganate (KMnO4) under normal conditions. Benzene is a stable aromatic compound and does not undergo typical alkene or alkane reactions with oxidizing agents like KMnO4.
When ethanol reacts with excess acidified KMnO4, it is oxidized to form ethanoic acid. The purple color of KMnO4 is decolorized to colorless Mn2+ ions during the reaction.
The evolved gas is carbon dioxide (CO2).
When potassium permanganate (KMnO4) reacts with formaldehyde (HCHO), it undergoes oxidation-reduction reaction. The purple color of KMnO4 fades as it gets reduced to Mn2+ ions, while formaldehyde is oxidized to formic acid (HCOOH) or carbon dioxide and water. Heat may be evolved during the reaction.
Baeyer's test for unsaturation using KMnO4 . if the sol'n retains the purple color of the reagent , then it is an alkane. if the color disappears with formation of brown precipitate ,it indicates presence of unsaturated HC
The ratio of equivalent weight of KMnO4 in acidic to basic medium is 1:2:5. In acidic medium, KMnO4 reacts as MnO4^- + 8H+ + 5e^- → Mn^2+ + 4H2O, requiring 5 equivalents, whereas in basic medium, it reacts as MnO4^- + 2H2O + 3e^- → MnO2 + 4OH^-, requiring 2 equivalents. In neutral medium, the equivalent weight is the same as in basic medium.
Potassium permanganate (KMnO4) is added slowly in titrations because it is a strong oxidizing agent that reacts quickly and vigorously with many compounds. By adding it slowly, you can control the reaction rate and prevent over-titration, ensuring accurate results. Additionally, adding it slowly allows for better observation of color changes that signal the endpoint of the titration.
The formula for potassium permanganate is KMnO4