What chemical tests can be used to distinguish between polymer and propene?

Answer 1

Propene is an alkene, whereas propane is an alkane. Thus, propene is an unsaturated molecule, having a carbon-carbon double bond. If you add bromine water, an aqueous solution of bromine, to the test tubes, you can tell which is propene, the alkene. The bromine reacts with and saturates the double bonds in alkenes, and so decolourises. The bromine does not decolourise when added to an alkane as it does not react. So, in conclusion:

• Add bromine water (brown) to the test tubes
• If the bromine water stays brown, the test tube contains propane
• If the bromine water goes colourless, the test tube contained propene.

Answer 2

1 propanol and 2propanol can be distinguished by lucas test. 2 propanol produces cloudiness within 5 minutes with lucas reagent. The cloudiness is due to the formation of immiscible alkyl halide. But 1 propanol does not react with lucas reagent at room temperature

Answer 3

Propene would satisfy the test for unsaturation, like the addition of bromine water which would yield decolorisation, while this would be absent for polymers, in which alll double bonds would be opened up.Thus all possible tests would :

1. Bromine water addition in carbon tetrachloride medium

2. Addition of Baeyer's reagent; decolorization of purple to colorless

3. Heating to give sooty flame indicates high degree of unsaturation.

Answer 4

One test that can be used is the Bromine Water test. When polymer reacts with Bromine Water, there will be no change in color, indicating that it is a polymer and not propene. Propene, on the other hand, will decolorize the Bromine Water due to its unsaturation.

Another test is the combustion test. When a small amount of the sample is burned, a polymer will produce a sooty flame and give off a burning plastic smell. Propene, being a hydrocarbon, will burn cleanly with a blue flame and give off carbon dioxide and water vapor.

Additionally, infrared (IR) spectroscopy can be used to distinguish between the two by analyzing the functional groups present in the molecule. Polymers will show characteristic functional groups of the repeating units, while propene will have specific peaks corresponding to the C=C bond.

Answer 5

tollens silver mirror test. it gives a silver mirror for aldehyde.