it goes from colourless to red/brown
Yes, the reaction is:Cl2 + 2 KBr = 2 KCl + Br2
When chlorine is added to sodium bromide solution, bromine is produced as one of the products through a redox reaction. The chlorine oxidizes the bromide ion to form bromine gas, while itself being reduced. This reaction is used to synthesize bromine from sodium bromide.
A stronger nucleophile or a more reactive metal could displace a bromide ion from solution. For example, a chloride ion could displace a bromide ion through a nucleophilic substitution reaction, or a more reactive metal like magnesium could displace bromide in a redox reaction.
The chemical equation is:2 KI + Cl2 = 2 KCl + I2
Yes, it is a primary way to extract chlorine gas.The most common means is to use electrolysis in a tank containing a solution of potassium chloride (KCl) or sodium chloride (NaCl, better known as table salt). The end result is potassium/sodium hydroxide in the solution--either one a very useful strong base, hydrogen gas, and chlorine gas.
Yes, the reaction is:Cl2 + 2 KBr = 2 KCl + Br2
Chlorine is a stronger oxidizer than elemental Bromine. So, when yellowish chlorine gas is bubbled through the Bromide solution, a red colour is formed which is Bromine. Chlorine oxidizes Bromide ions to elemental Bromine while itself is reduced to Chloride ions. So, the total reaction is: Cl2 + Br- ----> Br2 + Cl-
When chlorine is added to sodium bromide solution, bromine is produced as one of the products through a redox reaction. The chlorine oxidizes the bromide ion to form bromine gas, while itself being reduced. This reaction is used to synthesize bromine from sodium bromide.
Chlorine is a more reactive halogen than bromine, therefore, when chlorine gas is bubbled through a calcium bromide solution, the chlorine will take the place of the bromine. This is called an anionic single replacement (displacement) reaction. Cl2(g) + CaBr2(aq) --> Br2(l) + CaCl2(aq)
A stronger nucleophile or a more reactive metal could displace a bromide ion from solution. For example, a chloride ion could displace a bromide ion through a nucleophilic substitution reaction, or a more reactive metal like magnesium could displace bromide in a redox reaction.
You would get Sodium Chloride and Bromine. This is because Chlorine is a more reactive group 7, (halogen), element that bromine, we know this because it is above bromine in the periodic table group, it is therefore more electronegative. When the reaction occurs, the Chlorine displaces the Bromine and the solution turns brown.
The chemical equation is:2 KI + Cl2 = 2 KCl + I2
Yes, it is a primary way to extract chlorine gas.The most common means is to use electrolysis in a tank containing a solution of potassium chloride (KCl) or sodium chloride (NaCl, better known as table salt). The end result is potassium/sodium hydroxide in the solution--either one a very useful strong base, hydrogen gas, and chlorine gas.
As a stronger oxidizing agent than Iodine, Chlorine oxidizes the Iodide ions to Elementary Iodine, while itself gets reduced to Chloride. The equation for this reaction is:Cl2 + 2 I- ----> 2 Cl- + I2
KBr, or potassium bromide, is an example of an ionic compound. It is formed by the combination of a metal (potassium) and a non-metal (bromine) through ionic bonding. Potassium bromide is often used in medicine and photography.
One possible way to separate naphthalene and potassium bromide is through sublimation. Naphthalene can be sublimed by heating the mixture, allowing it to vaporize and then condense back into solid form. Since potassium bromide does not sublime easily, it would remain in the solid state and can be separated from the naphthalene vapor.
Yes, light can pass through a potassium permanganate solution to some extent. However, the intensity of light passing through will depend on the concentration of the solution and its thickness. Potassium permanganate is a deep purple color and will absorb some of the light passing through it.