All contain the same number of atoms: 6,022 140 857(74).10e23 (number of Avogadro).
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
Any of the diatomic molecules like H2 gas, O2 gas, N2 gas, etc.
O2, N2, Cl2, I2, as well as F2, Br2, and H2 are all diatomic elements.
This equation and finding the limiting reactant.2H2 + O2 -> 2H2O2 kg H2 (1000 g H/1 kg H)(1 mole H/2.016 grams)= 992 moles hydrogen16 kg O2 (1000 g/1 kg)(1 mole O2/32.0 grams)= 500 moles oxygenI suspect hydrogen limits. Let's see.992 mole H2 (1 mole O2/2 mole H2)= 496 moles O2You have just a bit more than this in oxygen, so enough and hydrogen limits. ( check by going the other way and see the hydrogen limits )So, hydrogen drives the reaction.2 kg H2 (1000 g/1 kg)(1 mole H2/ 2.016 g)(2 mole H2O/2 mole H2)(18.016 g/1 mole H2O)(1 kg/1000 g)= 17.87 kilograms water made=========================( you do the significant figures )
They are different elements. O2 is oxygen and F2 Florine
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
O2,N2,H2,F2,Cl2,Li2,Na2
H2 O2 Cl2 Br2 N2 I2 F2
H2, N2, O2, F2, Cl2, Br2, and I2
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
They are diatomic molecules. They are hydrogen (H2), nitrogen (N2), oxygen (O2), chlorine (Cl2), bromine (Br2), iodine (I2), astatine (As2), and fluorine (F2).
there are 7 : H2 N2 O2 F2 Cl2 Br2 & I2
Any of the diatomic molecules like H2 gas, O2 gas, N2 gas, etc.
H2, N2, O2, F2, Cl2, Br2, and I2 are all diatomic elements.
20 moles of Al will react with water to form 60 moles of H2 and 30 moles of O2, because of the stoichiometry 2:1 in getting H2 en O2 from water, and Al needing an oxidationstate of 3+, so 1 mole is oxidized by 3 moles of H2O.
Hydrogen H2; nitrogen, N2; oxygen, O2; fluorine, F2; chlorine, Cl2