Their number of atoms.
Use stoichometry to figure this out. 1 mole Fe * 56 g Fe ...............1 mole Fe
To determine the number of iron atoms in a 23.0 g iron block, you would first calculate the number of moles of iron using the molar mass of iron (55.85 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of iron to atoms.
magnesium oxide is MgO, and iron can FeO, Fe(2)O(3), or Fe(3)O(4) depending on the oxidation state ofe the iron.
most likely Magnesium-Chloride(MG?CL?) and Iron(FE?) The numbers depend on the oxidation states of iron and magnesium
When magnesium reacts with iron(II) nitrate [Fe(NO3)2], the magnesium replaces the iron in the compound, forming magnesium nitrate [Mg(NO3)2] and iron. The balanced chemical equation for this reaction is: 3Mg + 2Fe(NO3)2 → 3Mg(NO3)2 + 2Fe.
the answer is there number of atoms
Use stoichometry to figure this out. 1 mole Fe * 56 g Fe ...............1 mole Fe
To determine the number of iron atoms in a 23.0 g iron block, you would first calculate the number of moles of iron using the molar mass of iron (55.85 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of iron to atoms.
The equation for the reaction between iron sulfate (FeSO4) and magnesium (Mg) is: FeSO4 + Mg -> MgSO4 + Fe. This is a single displacement reaction where magnesium replaces iron in the iron sulfate compound, forming magnesium sulfate and elemental iron.
55.8 moles
magnesium oxide is MgO, and iron can FeO, Fe(2)O(3), or Fe(3)O(4) depending on the oxidation state ofe the iron.
Fe + MgSO4 --> FeSO4 + Mg Fe(iron)is more reactive than mg( magnesium) ........ therefore iron will displace magnesium....... hence it is a displacement reaction.............
It depends on the mass of iron. 1 mole Fe = 55.845g = 6.022 x 1023 atoms Fe
This mineral is olivine: (Mg, Fe)2SiO4.
most likely Magnesium-Chloride(MG?CL?) and Iron(FE?) The numbers depend on the oxidation states of iron and magnesium
The atomic mass of iron (Fe) is approximately 55.85 grams per mole.
When magnesium reacts with iron(II) nitrate [Fe(NO3)2], the magnesium replaces the iron in the compound, forming magnesium nitrate [Mg(NO3)2] and iron. The balanced chemical equation for this reaction is: 3Mg + 2Fe(NO3)2 → 3Mg(NO3)2 + 2Fe.