Ag+ is Silver, and Cl- is chlorine.
When silver and chlorine are combined, the amounts do not need to be changed since the charges become neutral, so all that is changed is the -ine to an -ide.
The final result is Silver Chloride. AgCl - Silver chloride
AgCl has a higher lattice energy than AgBr because Cl- is a smaller ion than Br-, resulting in stronger electrostatic interactions in AgCl.
No, AgCl is not organic. It is an inorganic compound composed of silver and chlorine.
The mole ratio of BaCl2 to AgCl is 1:2. This means that for every 1 mole of BaCl2, 2 moles of AgCl are produced in the chemical reaction.
There's 4 moles.
Yes, AgCl (silver chloride) has low solubility in water. It is sparingly soluble and forms a white precipitate when it is formed in solution.
AgCl is highly insoluble, as it is a precipitate.
The chemical compound name for AgCl is silver chloride.
AgCl has a higher lattice energy than AgBr because Cl- is a smaller ion than Br-, resulting in stronger electrostatic interactions in AgCl.
No, AgCl is not organic. It is an inorganic compound composed of silver and chlorine.
The mole ratio of BaCl2 to AgCl is 1:2. This means that for every 1 mole of BaCl2, 2 moles of AgCl are produced in the chemical reaction.
There's 4 moles.
AgCl is a white crystalline solid and is well known for its low solubility in water.
Yes, AgCl (silver chloride) has low solubility in water. It is sparingly soluble and forms a white precipitate when it is formed in solution.
(AgCl has Ksp = 1.8 x 10-10)-5.1 x 10-10
AgCl, or silver chloride, is a white solid at room temperature.
Yes, AgCl can be separated from NaCl by adding ammonia solution. AgCl is insoluble in ammonia, so it will precipitate out as a solid while NaCl remains in the solution. The two can then be filtered or separated by decantation.
To determine the mass of AgCl needed, first calculate the number of moles needed using the molarity equation: moles = molarity x volume (in L). Then, convert moles of AgCl to grams by using the molar mass of AgCl (107.87 g/mol for Ag and 35.45 g/mol for Cl). Finally, perform the calculation to find the grams of AgCl required.