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How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
Is 2-naphthol soluble in HCl?
No, 2-naphthol is not soluble in hydrochloric acid (HCl) because it is a nonpolar compound and HCl is a polar solvent.
What is balanced equation of AL2o3 plus HCL?
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
HCL CUSO4 equation?
The chemical equation for the reaction between hydrochloric acid (HCl) and copper (II) sulfate (CuSO4) is: 2 HCl + CuSO4 -> CuCl2 + H2SO4
Al metals react with HCL to form H2 and AlCl balanced equation?
The balanced chemical equation for the reaction of aluminum with hydrochloric acid (HCl) to form hydrogen gas (H2) and aluminum chloride (AlCl3) is: 2 Al + 6 HCl → 2 AlCl3 + 3 H2
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
Is 2-naphthol soluble in HCl?
No, 2-naphthol is not soluble in hydrochloric acid (HCl) because it is a nonpolar compound and HCl is a polar solvent.
Equation between na2co3 and hcl?
The chemical equation is:Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O
What is balanced equation of AL2o3 plus HCL?
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
How many moles of HCl and needed to react 2.4 moles of Al?
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
HCL CUSO4 equation?
The chemical equation for the reaction between hydrochloric acid (HCl) and copper (II) sulfate (CuSO4) is: 2 HCl + CuSO4 -> CuCl2 + H2SO4
Al metals react with HCL to form H2 and AlCl balanced equation?
The balanced chemical equation for the reaction of aluminum with hydrochloric acid (HCl) to form hydrogen gas (H2) and aluminum chloride (AlCl3) is: 2 Al + 6 HCl → 2 AlCl3 + 3 H2
What volume of 0.500m mgoh is required to neutralize 0.200l of 0.100m hcl?
Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
What is The equation between mgnisium nitride and HCl?
Eq:Mg3N2 + 6 HCl ----> 3 MgCl2 + 2 NH3
What is the balance equation for KMnO4 plus HCl?
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2
What is the pH of 10.0L of 0.0020 M HCL?
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
What is the major product from the treatment of propene with HCL?
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
