The N of 0.02 N acid stands for the "normality".
The normality is defined as the gram equivalent weight of a substance in a liter of solution.
so, a 0.02 acid would have 0.02 gram equivalents of acid per liter.
In short N means "normality" and stands for "g/l"
The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.
The (N) stands for Normal. 1 Normal is 28 ml of concentrated sulfuric acid added to deionized water for a final volume of 1 Liter (L). 18 N is roughly a 50 percent concentration sulfuric acid.
The n factor of boric acid is 1, as it donates only one proton in a reaction.
To prepare 0.1 N oxalic acid solution, you would need to dissolve 0.634 g of oxalic acid dihydrate (H2C2O4·2H2O) in distilled water and make up the solution to a final volume of 1 liter. This will give you a 0.1 N (normality) solution of oxalic acid.
To prepare N-phenylanthranilic acid indicator, dissolve 0.1 g of N-phenylanthranilic acid in 100 ml of ethanol or methanol. This will create a stock solution of the indicator that can be diluted further as needed for specific applications.
DNA stands for deoxyribonucleic acid. The "D" stands for deoxyribose, which is the sugar molecule in the backbone of the DNA strand. The "N" stands for nucleic, indicating that DNA is a type of nucleic acid. The "A" stands for acid, referring to the acidic nature of the molecule.
Acid. RNA = Ribonucleic acid.
002 is 2 and 020 is 20, so 020 is greater.
Carbonic acid
LySergic acid Diethylamide aka acid
Aspartoacylase breaks down N-acetylaspartic acid
DNA does stand for deoxyribonucleic acid and you spelled it exactly right.
It could stand for N/A -non aplickable
In means you
The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.
organic acid
Boric Acid