answersLogoWhite

0

reaction

User Avatar

Wiki User

11y ago

What else can I help you with?

Continue Learning about Chemistry
Related Questions

How do you factor 4qr - qr cubed?

To factor the expression 4qr - qr^3, we first notice that both terms have a common factor of qr. We can factor out qr to get qr(4 - r^2). Next, we recognize that 4 - r^2 is a difference of squares, which can be factored further as (2 + r)(2 - r). Therefore, the fully factored form of 4qr - qr^3 is qr(2 + r)(2 - r).


What does R-134A stand for?

In chemistry, this chemical compound, R-134A is the symbol for tetrafluoroethane. Tetrafluoroethane can be used as a solvent in organic chemistry.


A pair of opposite rays that both contain R?

↔QR


Why is the sum of two rational numbers always rational numbers?

Suppose p/q and r/s are rational numbers where p, q, r and s are integers and q, s are non-zero.Then p/q + r/s = ps/qs + qr/qs = (ps + qr)/qs. Since p, q, r, s are integers, then ps and qr are integers, and therefore (ps + qr) is an integer. q and s are non-zero integers and so qs is a non-zero integer. Consequently, (ps + qr)/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.


Point b is between q and r on qr and qb equals 20 br equals 10?

This isn't a question, even. It's a statement about a line segment, QR.


What has the author R A Witthaus written?

R. A. Witthaus has written: 'Essentials of chemistry' -- subject(s): Organic Chemistry, Chemistry, Pharmaceutical chemistry


Why is the difference between two rational numbers always a rational number?

Suppose x and y are two rational numbers. Therefore x = p/q and y = r/s where p, q, r and s are integers and q and s are not zero.Then x - y = p/q - r/s = ps/qs - qr/qs = (ps - qr)/qsBy the closure of the set of integers under multiplication, ps, qr and qs are all integers,by the closure of the set of integers under subtraction, (ps - qr) is an integer,and by the multiplicative properties of 0, qs is non zero.Therefore (ps - qr)/qs satisfies the requirements of a rational number.


What has the author William R Robinson written?

William R. Robinson has written: 'Chemistry' -- subject(s): Chemistry 'General chemistry with qualitative analysis' -- subject(s): Analytic Chemistry, Chemistry, Chemistry, Analytic, Qualitative


Why is the difference of two rational numbers are rational numbers?

Suppose A and B are two rational numbers. So A = p/q where p and q are integers and q > 0 and B = r/s where r and s are integers and s > 0. Then A - B = p/q - r/s = ps/qs - qr/qs = (ps - qr)/qs Now, p,q,r,s are integers so ps and qr are integers and so x = ps-qr is an integer and y = qs is an integer which is > 0 Thus A-B can be written as a ratio of two integers, x/y where y>0. Therefore, A-B is rational.


Why is the sum or product of two rational numbers rational?

Suppose p/q and r/s are rational numbers where p, q, r and s are integers and q, s are non-zero.Then p/q + r/s = ps/qs + qr/qs = (ps + qr)/qs.Since p, q, r, s are integers, then ps and qr are integers, and therefore (ps + qr) is an integer.q and s are non-zero integers and so qs is a non-zero integer.Consequently, (ps + qr)/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.Also p/q * r/s = pr/qs.Since p, q, r, s are integers, then pr and qs are integers.q and s are non-zero integers so qs is a non-zero integer.Consequently, pr/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.


What has the author John R Amend written?

John R. Amend has written: 'General, organic, and biological chemistry' -- subject(s): Biochemistry, Chemistry, Chemistry, Organic, Organic Chemistry


What has the author R Nelson Smith written?

R. Nelson Smith has written: 'Chemistry; a quantitative approach' -- subject(s): Analytic Chemistry, Chemistry, Quantitative