0
What else can I help you with?
In organic chemistry what does the r stand for example rh cl2 - rcl hcl?
r stands for "the rest of a molecule". Since there are about 20 different amino acids, it could be any one of the 20.
What is the difference between the R and S configurations in organic chemistry?
In organic chemistry, the R and S configurations are used to describe the spatial arrangement of atoms around a chiral center. The R configuration indicates a clockwise arrangement of substituents, while the S configuration indicates a counterclockwise arrangement.
What is the difference between the R and S configuration in organic chemistry?
In organic chemistry, the R and S configurations refer to the spatial arrangement of atoms around a chiral center. The R configuration indicates a clockwise arrangement of substituents, while the S configuration indicates a counterclockwise arrangement. This distinction helps to identify the stereochemistry of molecules.
Who was the winner of noble prize in chemistry in 2005?
It is shared by Yves Chauvin, Robert H. Grubbs and Richard R. Schrock.
Why did Richard R. Schrock win The Nobel Prize in Chemistry in 2005?
Richard R. Schrock won the Nobel Prize in Chemistry in 2005 for his work on the development of the metathesis method in organic synthesis. This method allows for the efficient and environmentally friendly production of complex molecules, which has had a significant impact on the fields of pharmaceuticals, materials science, and biotechnology.
How do you factor 4qr - qr cubed?
To factor the expression 4qr - qr^3, we first notice that both terms have a common factor of qr. We can factor out qr to get qr(4 - r^2). Next, we recognize that 4 - r^2 is a difference of squares, which can be factored further as (2 + r)(2 - r). Therefore, the fully factored form of 4qr - qr^3 is qr(2 + r)(2 - r).
What does R-134A stand for?
In chemistry, this chemical compound, R-134A is the symbol for tetrafluoroethane. Tetrafluoroethane can be used as a solvent in organic chemistry.
A pair of opposite rays that both contain R?
↔QR
Why is the sum of two rational numbers always rational numbers?
Suppose p/q and r/s are rational numbers where p, q, r and s are integers and q, s are non-zero.Then p/q + r/s = ps/qs + qr/qs = (ps + qr)/qs. Since p, q, r, s are integers, then ps and qr are integers, and therefore (ps + qr) is an integer. q and s are non-zero integers and so qs is a non-zero integer. Consequently, (ps + qr)/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.
Point b is between q and r on qr and qb equals 20 br equals 10?
This isn't a question, even. It's a statement about a line segment, QR.
What has the author R A Witthaus written?
R. A. Witthaus has written: 'Essentials of chemistry' -- subject(s): Organic Chemistry, Chemistry, Pharmaceutical chemistry
Why is the difference between two rational numbers always a rational number?
Suppose x and y are two rational numbers. Therefore x = p/q and y = r/s where p, q, r and s are integers and q and s are not zero.Then x - y = p/q - r/s = ps/qs - qr/qs = (ps - qr)/qsBy the closure of the set of integers under multiplication, ps, qr and qs are all integers,by the closure of the set of integers under subtraction, (ps - qr) is an integer,and by the multiplicative properties of 0, qs is non zero.Therefore (ps - qr)/qs satisfies the requirements of a rational number.
What has the author William R Robinson written?
William R. Robinson has written: 'Chemistry' -- subject(s): Chemistry 'General chemistry with qualitative analysis' -- subject(s): Analytic Chemistry, Chemistry, Chemistry, Analytic, Qualitative
Why is the difference of two rational numbers are rational numbers?
Suppose A and B are two rational numbers. So A = p/q where p and q are integers and q > 0 and B = r/s where r and s are integers and s > 0. Then A - B = p/q - r/s = ps/qs - qr/qs = (ps - qr)/qs Now, p,q,r,s are integers so ps and qr are integers and so x = ps-qr is an integer and y = qs is an integer which is > 0 Thus A-B can be written as a ratio of two integers, x/y where y>0. Therefore, A-B is rational.
Why is the sum or product of two rational numbers rational?
Suppose p/q and r/s are rational numbers where p, q, r and s are integers and q, s are non-zero.Then p/q + r/s = ps/qs + qr/qs = (ps + qr)/qs.Since p, q, r, s are integers, then ps and qr are integers, and therefore (ps + qr) is an integer.q and s are non-zero integers and so qs is a non-zero integer.Consequently, (ps + qr)/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.Also p/q * r/s = pr/qs.Since p, q, r, s are integers, then pr and qs are integers.q and s are non-zero integers so qs is a non-zero integer.Consequently, pr/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.
What has the author John R Amend written?
John R. Amend has written: 'General, organic, and biological chemistry' -- subject(s): Biochemistry, Chemistry, Chemistry, Organic, Organic Chemistry
What has the author R Nelson Smith written?
R. Nelson Smith has written: 'Chemistry; a quantitative approach' -- subject(s): Analytic Chemistry, Chemistry, Quantitative
