Chromium
Manganese = 25, 7B
b
1s2 2s2 2p6 3s2 3p6 4s2 3d5
1s2 2s2 2p6 3s2 3p6 4s2 3d6 That is for an iron atom. If you mean an Fe+3 ion 1s2 2s2 2p6 3s2 3p6 3d5
1s2 2s2 2p6 3s2 3p6 4s1 3d5
The complete electron configuration for the chromium(III) ion is 1s22s22p63s23p64s03d3.
b
1s2 2s2 2p6 3s2 3p6 4s2 3d5
1s2 2s2 2p6 3s2 3p6 4s2 3d6 That is for an iron atom. If you mean an Fe+3 ion 1s2 2s2 2p6 3s2 3p6 3d5
1s2 2s2 2p6 3s2 3p6 4s1 3d5
The complete electron configuration for the chromium(III) ion is 1s22s22p63s23p64s03d3.
It would be 1s2 2s2 2p6 3s2 3p6 3d5 4s1.
Fe(III) is 3d5 this is because Fe(0) is 3d6 4s2
The electronic configuration of chromium is 1s2 2s2 2p6 3s2 3p6 3d5 4s1.
well you see, 1s2 2s2 2p6 3s2 3p6 3d5 4s2 is manganese if it becomes 2+ then it loses 4s2 first so it would now look like 1s2 2s2 2p6 3s2 3p6 3d5 which is manganese 2+ but has the spdf of vanadium hope im helpful
l s2 2s22p6 3s23p63d4
Chromium (24Cr) electron configuration: [Ar] 3d5 4s1 Complete [1s2, 2s2 2p6, 3s2 3p6] 3d5, 4s1
1s2 2s2 2p6 3s2 3p6 3d5 4s1 So 5 full orbitals and a half filled 3d orbital