I know Hydrogen and Helium for sure, not sure about the other elements.
The noble gases.
BCl3 and BEH2 obey the octet rule because Boron and Beryllium are exceptions to the octet rule and can have stable electron configurations with less than 8 electrons. Cl3CF, NO, and SbF5 do not obey the octet rule because they have incomplete or expanded valence shells.
It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell. It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell.
most metals do not follow the octet rule. when an atom has access to the D orbitals it usually follows the 18-electron rule (transition metals). non transition or F block elements usually contain a d orbital (when present) that is below the s and p orbitals in energy and do not usually use D electrons in bonding.
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
The oxygen atoms in the ion do obey the octet rule. The phosphorus atom has more than eight electrons in its valence shell. It is because of the existence of vacant 3d orbitals.
The elements can be described by dot structure. Metals combine with other elements to make its octet complete.
No chlorine oxides will obey the octet rule.
no it does not follow octet rule
Group 19 elements have 8 valence electrons (obey octet rule) and are hence stable.
It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell. It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell.
Cs2, NO3, and PO43 do not obey the octet rule because they have an odd number of valence electrons. CI4 and SCI4 do not obey the octet rule because the central atom (Cl or S) exceeds the octet by having more than eight valence electrons.
BCl3 and BEH2 obey the octet rule because Boron and Beryllium are exceptions to the octet rule and can have stable electron configurations with less than 8 electrons. Cl3CF, NO, and SbF5 do not obey the octet rule because they have incomplete or expanded valence shells.
It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell. It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell.
most metals do not follow the octet rule. when an atom has access to the D orbitals it usually follows the 18-electron rule (transition metals). non transition or F block elements usually contain a d orbital (when present) that is below the s and p orbitals in energy and do not usually use D electrons in bonding.
Hydrogen is the atom that doesn't always obey the octet rule. It only needs 2 electrons to have a full outer shell, rather than the 8 electrons typically required by the octet rule. Oxygen and bromine usually follow the octet rule.
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
H and l