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Chloride and bromine are not likely to form an ionic bond because only one of them, chloride, is an ion.If the questioner meant chlorine and bromine, they are not likely to form an ionic bond with each other, because there is too little difference in their electronegativities. However, both of them are very likely to form ionic bonds with less electronegative elements, such as metals.
Yes, a Bromine atom can bond to another similar Bromine atom, to make a Bromine molecule: Br2
No, selenium and bromine would not form a covalent bond. Bromine typically forms ionic bonds with other elements due to its high electronegativity, while selenium can form covalent bonds with other nonmetals. In this case, selenium and bromine would likely form an ionic bond rather than a covalent bond.
When two bromine atoms bond together, they will share one pair of electrons, forming a covalent bond. This will create a stable Br2 molecule, with each bromine atom having a full outer electron shell. The bond will be nonpolar since bromine atoms share the electrons equally due to having identical electronegativities.
The bond between rubidium and bromine typically forms an ionic bond due to the large difference in electronegativity between the two elements. Rubidium tends to donate its outer electron to bromine, resulting in the formation of rubidium cations and bromide anions.
Chloride and bromine are not likely to form an ionic bond because only one of them, chloride, is an ion.If the questioner meant chlorine and bromine, they are not likely to form an ionic bond with each other, because there is too little difference in their electronegativities. However, both of them are very likely to form ionic bonds with less electronegative elements, such as metals.
Yes, a Bromine atom can bond to another similar Bromine atom, to make a Bromine molecule: Br2
No, selenium and bromine would not form a covalent bond. Bromine typically forms ionic bonds with other elements due to its high electronegativity, while selenium can form covalent bonds with other nonmetals. In this case, selenium and bromine would likely form an ionic bond rather than a covalent bond.
Nitrogen and bromine will form a covalent bond; they are both nonmetals.
Francium would likely form an ionic bond with bromine by transferring its single valence electron to bromine in order to achieve a stable electron configuration. This would result in the formation of francium bromide (FrBr).
When two bromine atoms bond together, they will share one pair of electrons, forming a covalent bond. This will create a stable Br2 molecule, with each bromine atom having a full outer electron shell. The bond will be nonpolar since bromine atoms share the electrons equally due to having identical electronegativities.
Bromine forms a diatomic molecule, so it has a covalent bond.
Bromine is a nonmetal as well as chlorine. A bond between a nonmetal and a nonmetal is a covalent bond.
The bond between rubidium and bromine typically forms an ionic bond due to the large difference in electronegativity between the two elements. Rubidium tends to donate its outer electron to bromine, resulting in the formation of rubidium cations and bromide anions.
The bond formed between the bromine atoms in a bromine molecule is a covalent bond. In a covalent bond, the atoms share a pair of electrons to achieve a stable electron configuration.
Beryllium would most likely form an ionic bond with bromine (Br) since beryllium typically loses its two valence electrons to form a 2+ cation, while bromine tends to gain one electron to form a 1- anion. This charge transfer allows for the formation of an ionic bond between beryllium and bromine.
No, a bromine-bromine bond is nonpolar because bromine atoms have similar electronegativities. This results in a symmetrical distribution of electron density around the atoms.