If pepsin, an enzyme that breaks down proteins, is added to sodium hydroxide (NaOH), a strong base, the high pH of the NaOH will denature and inactivate the pepsin enzyme. Denaturation is the process where the protein loses its shape and function due to changes in pH, temperature, or other conditions. This would prevent pepsin from being able to digest proteins in the presence of NaOH.
The pH of pepsin in NaOH would depend on the concentration of NaOH added. Pepsin is an enzyme that functions best at acidic pH levels, around pH 2.0. Adding NaOH, a base, would increase the pH, potentially inactivating the pepsin enzyme as it moves away from its optimal pH range for activity.
Hey, I'm still a student, so I cannot guarantee that my answer is entirely correct, however, this is what my answer was on a similar question in a matsec paper: > Since pepsin is an enzyme, which works best in acidic environment, such as the one provided i the stomach, no change/ reaction would be observed, because NaOH is an alkaline solution. Therefore, pepsin would not be able to work in an environment with such great pH difference to its optimum. I hope that helped somehow although my answer is probably very late :P Good luck, Angelina
NaOH turns pink when phenolphthalein is added.
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
In the presence of aqueous NaOH, phenol undergoes nucleophilic aromatic substitution reaction to form sodium phenoxide. When CCl4 is added, no reaction occurs as CCl4 is non-reactive towards phenoxide ion.
The pH of pepsin in NaOH would depend on the concentration of NaOH added. Pepsin is an enzyme that functions best at acidic pH levels, around pH 2.0. Adding NaOH, a base, would increase the pH, potentially inactivating the pepsin enzyme as it moves away from its optimal pH range for activity.
Hey, I'm still a student, so I cannot guarantee that my answer is entirely correct, however, this is what my answer was on a similar question in a matsec paper: > Since pepsin is an enzyme, which works best in acidic environment, such as the one provided i the stomach, no change/ reaction would be observed, because NaOH is an alkaline solution. Therefore, pepsin would not be able to work in an environment with such great pH difference to its optimum. I hope that helped somehow although my answer is probably very late :P Good luck, Angelina
it is a base
The alkali in NaOH would burn your skin.
NaOH turns pink when phenolphthalein is added.
it decreases
nothing
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
In the presence of aqueous NaOH, phenol undergoes nucleophilic aromatic substitution reaction to form sodium phenoxide. When CCl4 is added, no reaction occurs as CCl4 is non-reactive towards phenoxide ion.
Nothing.
Quantity matters. If there is a lot of buffer (in terms of moles) and relatively little NaOH then the buffer will prevent any change in pH. If there is relatively more NaOH than buffer, then of course the pH will rise.
The question appears to be: What happens if H2O is added to NaOH? NaOH will split into ionic molecules, and will heat up the water. In fact, adding water to NaOH is dangerous as it can cause splashes from extreme rise in temperatures.