NaBr + AgNO3= AgBr + NaNO3
The color of the solution changes to yellow from colorless... due to formation of silver bromide.
When silver nitrate is added to a solution containing bromide ions, a white precipitate of silver bromide will form. This is due to a chemical reaction between the silver nitrate and bromide ions, resulting in the insoluble silver bromide precipitate.
When silver nitrate is added to carbon tetrachloride, the silver nitrate will not dissolve as it is insoluble in carbon tetrachloride. The two substances will remain separate, with the silver nitrate forming a precipitate at the bottom of the container.
Silver nitrate is commonly used to test for the presence of halide ions, such as chloride, bromide, and iodide ions. When silver nitrate is added to a solution containing these ions, characteristic precipitates are formed: white for chloride ions, cream for bromide ions, and yellow for iodide ions.
Nitric acid is added before silver nitrate in the bromine test to oxidize any interfering substances that could react with silver nitrate. This helps to prevent false positive results and ensures that the precipitation reaction with silver nitrate is due to the presence of bromide ions.
When clhlorine is added to silver nitrate a milky white precipitate of Silver Chloride is formed. Potassium nitrate is also formed. When chlorine is added to potassium chloride nothing visible happens but the solutiuon become more acidic.
When silver nitrate is added to a solution containing bromide ions, a white precipitate of silver bromide will form. This is due to a chemical reaction between the silver nitrate and bromide ions, resulting in the insoluble silver bromide precipitate.
When silver nitrate is added to carbon tetrachloride, the silver nitrate will not dissolve as it is insoluble in carbon tetrachloride. The two substances will remain separate, with the silver nitrate forming a precipitate at the bottom of the container.
silver chloride should precipitate out.
Silver nitrate is commonly used to test for the presence of halide ions, such as chloride, bromide, and iodide ions. When silver nitrate is added to a solution containing these ions, characteristic precipitates are formed: white for chloride ions, cream for bromide ions, and yellow for iodide ions.
Nitric acid is added before silver nitrate in the bromine test to oxidize any interfering substances that could react with silver nitrate. This helps to prevent false positive results and ensures that the precipitation reaction with silver nitrate is due to the presence of bromide ions.
When clhlorine is added to silver nitrate a milky white precipitate of Silver Chloride is formed. Potassium nitrate is also formed. When chlorine is added to potassium chloride nothing visible happens but the solutiuon become more acidic.
When silver nitrate is added to distilled water, it will dissociate into silver ions (Ag+) and nitrate ions (NO3-), causing the solution to become slightly acidic. When silver nitrate is added to a salt solution, it will react with the salt to form a precipitate of insoluble silver salt, such as silver chloride (AgCl). This will cause a milky white precipitate to form in the solution.
Impossale to tell. Added: If the salt solution contains chloride ion (eg. from table salt, NaCl) then silver chloride will precipitate. Both sodium and nitrate ions stay unchanged in solution.Ag+aq + Cl-aq --> AgCls
When silver nitrate is added to starch, no reaction occurs. Silver nitrate does not react with starch molecules.
When acid zinc chloride is added to silver nitrate, a displacement reaction occurs where zinc replaces silver in the compound. This results in the formation of zinc nitrate and silver metal precipitate. The silver metal appears as a solid, while zinc nitrate remains in solution.
When sodium bicarbonate is added to silver nitrate, a white precipitate of silver carbonate is formed along with sodium nitrate solution. The reaction can be represented as: NaHCO3 + AgNO3 → Ag2CO3 + NaNO3 + H2O + CO2.
When silver nitrate is added to barium chloride, a white precipitate of silver chloride forms because silver chloride is insoluble in water. This occurs due to a double displacement reaction where the silver ions from silver nitrate react with the chloride ions from barium chloride to form silver chloride. The remaining solution would contain barium nitrate as the other product of the reaction.