CaCl2(Calcium Chloride)and H2CO3(Carbonic acid) are formed and as H2CO3 is very unstable and weak so it turns into H2O(water) and CO2 (Carbon-di-oxide).
The reactions are :
CaCO3 +2HCl =CaCl2+H2CO3
H2CO3=H2O+CO2
firstly this is a nuetralisation reaction between a strong acid and a base. when a carbonates reacts with other elements it forms a salt, water and carbon dioxide. the salt formed is calcium choride which is a white powdered substance
When hydrochloric acid (HCl) is mixed with calcium carbonate (CaCO3), it forms calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O). This is a chemical reaction where the calcium carbonate reacts with the hydrochloric acid to produce these new compounds.
When CaCl2 reacts with NaHCO3, the products formed are CaCO3 (calcium carbonate), NaCl (sodium chloride), and H2O (water).
You can find a answer fromCalcium carbonate - Wikipedia
Yes, if HCl (hydrochloric acid) spilled into the CaCO3 sample, a chemical reaction will occur. This will alter the mass of CaCO3 present in the sample, leading to an error in the reported percent CaCO3 due to the loss of some CaCO3 in the reaction with HCl.
The molecular equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: HCl + CaCO3 → CaCl2 + CO2 + H2O. This reaction produces calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O) as products.
When hydrochloric acid (HCl) is mixed with calcium carbonate (CaCO3), it forms calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O). This is a chemical reaction where the calcium carbonate reacts with the hydrochloric acid to produce these new compounds.
They are molecules.
When CaCl2 reacts with NaHCO3, the products formed are CaCO3 (calcium carbonate), NaCl (sodium chloride), and H2O (water).
CaCO3 + HCl --> CaHCO3 or with excess of HCl CaCO3 + 2HCl --> CaCl2 +CO2 + H2O
You can find a answer fromCalcium carbonate - Wikipedia
Yes, if HCl (hydrochloric acid) spilled into the CaCO3 sample, a chemical reaction will occur. This will alter the mass of CaCO3 present in the sample, leading to an error in the reported percent CaCO3 due to the loss of some CaCO3 in the reaction with HCl.
This salt is magnesium chloride (MgCl2).
The molecular equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: HCl + CaCO3 → CaCl2 + CO2 + H2O. This reaction produces calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O) as products.
The balanced equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + H2O + CO2.
CaCO3(s) + 2 HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l) 500 L * (1.40 mol HCl/1 L HCl) * (1 mol CaCO3/2 mol HCl) * (100.09 g CaCO3/1 mol CaCO3) = 35031.5 g CaCO3 35031.5 g * (1 kg/1000 g) = 35.0315 kg Therefore, about 35.03 kilograms of calcium carbonate is needed to neutralize 500 liters of 1.40 M hydrochloric acid.
The chemical reaction is:CaCl2+ Na2CO3 = CaCO3(s) + 2 NaCl
The reaction between chalk (calcium carbonate, CaCO3) and hydrochloric acid (HCl) can be represented by the chemical equation: CaCO3 + 2HCl → CaCl2 + CO2 + H2O