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CaCl2(Calcium Chloride)and H2CO3(Carbonic acid) are formed and as H2CO3 is very unstable and weak so it turns into H2O(water) and CO2 (Carbon-di-oxide).
The reactions are :
CaCO3 +2HCl =CaCl2+H2CO3
H2CO3=H2O+CO2
firstly this is a nuetralisation reaction between a strong acid and a base. when a carbonates reacts with other elements it forms a salt, water and carbon dioxide. the salt formed is calcium choride which is a white powdered substance
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When CaCo3 is added to Hcl what is formed?
Calcium chloride, carbon dioxide and water
What is purpose of adding HCl to the CaCO3 -H2O mixture prior to dilute?
It is the only way of dissolving CaCO3. HCl + CaCO3 --> Ca2+ + H2O + CO2 In neutral water CaCO3 is insoluble.
When hcl is mixed with calcium carbonate what is formed?
carbon dioxide and water
How do you determine the number of kilograms of CaCO3 needed to neutralize 500 L of 1.40 M HCl?
CaCO3(s) + 2 HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l) 500 L * (1.40 mol HCl/1 L HCl) * (1 mol CaCO3/2 mol HCl) * (100.09 g CaCO3/1 mol CaCO3) = 35031.5 g CaCO3 35031.5 g * (1 kg/1000 g) = 35.0315 kg Therefore, about 35.03 kilograms of calcium carbonate is needed to neutralize 500 liters of 1.40 M hydrochloric acid.
What products do you get when CaCl2 plus NaHCO3?
Nacl+Hcl+CaCO3
When CaCo3 is added to Hcl what is formed?
Calcium chloride, carbon dioxide and water
What is purpose of adding HCl to the CaCO3 -H2O mixture prior to dilute?
It is the only way of dissolving CaCO3. HCl + CaCO3 --> Ca2+ + H2O + CO2 In neutral water CaCO3 is insoluble.
If you have the chemical equation caco3 and hcl equal cacl3 etc. are caco3 and hcl particles molecules or ions?
They are molecules.
When hcl is mixed with calcium carbonate what is formed?
carbon dioxide and water
What is the Balanced equation for calcium carbonate and hydrochloric acid reacting?
CaCO3 + HCl --> CaHCO3 or with excess of HCl CaCO3 + 2HCl --> CaCl2 +CO2 + H2O
What salt would be formed when Mg and HCl are mixed?
This salt is magnesium chloride (MgCl2).
How do you determine the number of kilograms of CaCO3 needed to neutralize 500 L of 1.40 M HCl?
CaCO3(s) + 2 HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l) 500 L * (1.40 mol HCl/1 L HCl) * (1 mol CaCO3/2 mol HCl) * (100.09 g CaCO3/1 mol CaCO3) = 35031.5 g CaCO3 35031.5 g * (1 kg/1000 g) = 35.0315 kg Therefore, about 35.03 kilograms of calcium carbonate is needed to neutralize 500 liters of 1.40 M hydrochloric acid.
What is formed when calcuim chloride and sodium carbonate are mixed?
The chemical reaction is:CaCl2+ Na2CO3 = CaCO3(s) + 2 NaCl
What products do you get when CaCl2 plus NaHCO3?
Nacl+Hcl+CaCO3
What is the equation for calcium carbonate with hydrochloric acid?
You can find a answer fromCalcium carbonate - Wikipedia
What volume of a 0.10 mol dm-3 solution of HCl is required to react with 10.0 g of CaCO3?
2 HCl + CaCO3 = CaCl2 + CO2 + H2O Therefore it takes twice as many moles of HCl to react with CaCO3 Mol CaCO3 = mass / formulae weight = 10 / 40.08 + 14.01 + 3(16.00) = 10 / 102.09 = 0.0980 mol Mol HCl = 2 x 0.0980 = 0.1959 mol Volume HCl = mol / c = 0.1959 / 0.10 = 1.9591 L Volume required to react of HCl = 1.9591 L
How many moles of HCl can 0.055 g of calcium carbonate neutralize?
First write the balanced chemical equation for this reaction CaCO3+2HCl-->CaCl2+H2O+CO2 It is clear from this equation that one mol of HCl can react with half a mol of CaCO3. Thus, one half of .025 mols CaCO3 will react with .025 mols HCl. That makes .0125 mols CaCO3.
