Copper sulfate dissolves in water, it does not react.
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
Anhydrous copper sulfate is CuSO4, while water is H2O. When anhydrous copper sulfate reacts with water, it forms hydrated copper sulfate, which is CuSO4·5H2O.
When copper oxide reacts with sulfuric acid, copper sulfate and water are formed. This chemical reaction can be represented by the equation: CuO + H2SO4 -> CuSO4 + H2O.
When copper(II) carbonate reacts with sulfuric acid, it forms copper(II) sulfate, carbon dioxide, and water. The balanced chemical equation for the reaction is: CuCO3 (s) + H2SO4 (aq) → CuSO4 (aq) + CO2 (g) + H2O (l)
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
Let's see! CuO + H2SO4 --> CuSO4 + H2O ======================== This reaction is what I think would theoretically happen here; a salt, copper sulfate, and water produced.
Anhydrous copper sulfate is CuSO4, while water is H2O. When anhydrous copper sulfate reacts with water, it forms hydrated copper sulfate, which is CuSO4·5H2O.
When copper oxide reacts with sulfuric acid, copper sulfate and water are formed. This chemical reaction can be represented by the equation: CuO + H2SO4 -> CuSO4 + H2O.
When copper(II) carbonate reacts with sulfuric acid, it forms copper(II) sulfate, carbon dioxide, and water. The balanced chemical equation for the reaction is: CuCO3 (s) + H2SO4 (aq) → CuSO4 (aq) + CO2 (g) + H2O (l)
CuCO3 + H2SO4 -> CuSO4 + H2O + CO2 copper(II) carbonate + sulphuric acid -> copper(II) sulphate water + carbon dioxide
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
Sulphurous acid is formed H2O + SO2 ----> H2SO3
H2O CuSo4 Ca2So4
Copper sulfate is formed when copper oxide reacts with sulfuric acid.