nothing will happen as copper is more reactive than silver.
The iron is more reactive than copper so when the iron nail is immersed in copper sulphate the iron takes sulphate ion from the copper sulphate and copper metal is deposited on top of the iron so that the nail will then look like a copper nail.The chemical reaction is called a replacement reaction, and is chemically represented as : CuSO4(compound in solution) + Fe(metal) ------>Cu(deposited metal) + FeSO4.
When a silver spoon is kept in an aqueous solution of copper sulfate, a redox reaction takes place where silver displaces copper from the solution. As a result, silver ions in the solution get reduced and deposit copper onto the spoon. This process is known as displacement reaction, where a more reactive metal displaces a less reactive metal in a compound.
As the concentration of H₃O⁺ increases in an aqueous solution, the pH decreases, shifting the equilibrium of the autoionization of water to the left. This results in a decrease in the concentration of hydroxide ions (OH⁻) in the solution.
When iron nails are placed in copper sulphate solution, a displacement reaction occurs where iron replaces copper in the solution to form iron sulphate and copper metal. The word equations for the reactions involved are: Iron (s) + Copper sulphate (aq) -> Iron sulphate (aq) + Copper (s)
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
Sh!t happens.
The iron is more reactive than copper so when the iron nail is immersed in copper sulphate the iron takes sulphate ion from the copper sulphate and copper metal is deposited on top of the iron so that the nail will then look like a copper nail.The chemical reaction is called a replacement reaction, and is chemically represented as : CuSO4(compound in solution) + Fe(metal) ------>Cu(deposited metal) + FeSO4.
When a silver spoon is kept in an aqueous solution of copper sulfate, a redox reaction takes place where silver displaces copper from the solution. As a result, silver ions in the solution get reduced and deposit copper onto the spoon. This process is known as displacement reaction, where a more reactive metal displaces a less reactive metal in a compound.
Double Replacement
i think that it would be displaced .... wont it?
the solution turns green and the nails develop a brown deposit which is copper. the iron displaces the copper in the copper sulphate solution. This is because iron is more reactive than copper.
As the concentration of H₃O⁺ increases in an aqueous solution, the pH decreases, shifting the equilibrium of the autoionization of water to the left. This results in a decrease in the concentration of hydroxide ions (OH⁻) in the solution.
Nothing. Gold is a noble metal- it is not displaced by iron.
When iron nails are placed in copper sulphate solution, a displacement reaction occurs where iron replaces copper in the solution to form iron sulphate and copper metal. The word equations for the reactions involved are: Iron (s) + Copper sulphate (aq) -> Iron sulphate (aq) + Copper (s)
it will clean 6 pennies to a fair but noticeable shine
The link below is a video on what will happen.
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)