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Well what chemically happens is an exchage of electrons. In an ionic bond, a metal (gold in this case) reacts with a non-metal (chlorine) to form an ionic compound. So Gold, or Au, most commonly has a charge of 3+. This means that normally to have a full outer shell of electrons, gold needs to give up three electrons, which is a loss of 3 negatives, which gives it a postivie charge. For chlorine to be 'happy' and have a full outer shell, it needs to gain one electron giving it a charge of 1-. These elements will only give up their electrons in specific situations and one is a bond. When chlorine gets put into an area with gold, then the chlorine takes an electron off of the gold, but since gold still needs to lose more electrons, then for every one gold atom losing electrons there must be 3 chlorine atoms taking them away. When this happens yu get a postively charged ion, Au+3 and three negatively charged ions, Cl-1. Since one of these ions is positive and the other negative, they act the same way as two different poles of a magnet would react. They attract to each other and stick together. Since they are now stuck together we know them as the compound AuCl3 or gold (III) chloride. (the III is a roman numeral for one, representing which type of gold was reacting) And that's whats happening when you put some solid gold into a chamber full of chlorine gas!

Here is the chemical formula just in case you want to see it:

2Au(s) + 3Cl2(g) --> 2AuCl3(s) Also if you are wondering, chlorine comes in pairs in its naturally occurring state, so we have to increase the number of gold around in order to properly react.

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