The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
The balanced chemical equation for the reaction of Sn with HCl to produce H2 gas is: Sn + 2HCl → SnCl2 + H2. According to the equation, 1 mole of Sn produces 1 mole of H2 gas, thus if 6.75 moles of Sn is consumed, then 6.75 moles of H2 gas will be produced.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
To find the number of moles, first convert the mass to grams (220 mg = 0.220 g). Then, calculate the number of moles using the formula: moles = mass / molar mass. The molar mass of CO2 is about 44 g/mol, so there are approximately 0.005 moles of CO2 in 220 mg.
.5 moles of tin because the half reaction for tin is Sn+4 + 2e- -> Sn+2 since there are 2 electrons needed, for one mole of Sn, 1 faraday would only produce a half of a mole of Sn.
The number 2.20 moles of Sn equals 261.14 grams. This is a taught in biology.
To find the grams of Sn formed, we first need to calculate the number of moles of SnO2 in 12.5 grams. Then, we use the stoichiometry of the reaction to relate the number of moles of SnO2 to the number of moles of Sn. Finally, we convert the moles of Sn to grams using the molar mass of Sn.
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
The balanced chemical equation for the reaction of Sn with HCl to produce H2 gas is: Sn + 2HCl → SnCl2 + H2. According to the equation, 1 mole of Sn produces 1 mole of H2 gas, thus if 6.75 moles of Sn is consumed, then 6.75 moles of H2 gas will be produced.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
2.09 moles Sn (6.022 X 10^23 atoms / 1 mole Sn) = 1.26 X 10^24 atoms of tin
Approx. 4 moles.
To find the number of moles, first convert the mass to grams (220 mg = 0.220 g). Then, calculate the number of moles using the formula: moles = mass / molar mass. The molar mass of CO2 is about 44 g/mol, so there are approximately 0.005 moles of CO2 in 220 mg.
.5 moles of tin because the half reaction for tin is Sn+4 + 2e- -> Sn+2 since there are 2 electrons needed, for one mole of Sn, 1 faraday would only produce a half of a mole of Sn.
To determine the empirical formula, first convert the grams of each element to moles by dividing by their respective molar masses. Next, find the ratio of moles of each element to each other. Finally, divide by the smallest number of moles to get a whole number ratio. In this case, the empirical formula is SnF2 as the ratio of moles of Sn to F is 1:2.
No sn data I can find. You will have to check on line auctions for prices.
I assume by " much " you mean grams tin. Balanced equation first.Sn + 4HCl -> SnCl4 + 2H2Now, find moles HCl by......Molarity = moles of solute/Liters of solution ( 32.0 ml = 0.032 Liters )1.75 M HCl = X moles/0.032 liters= 0.056 moles HCl=============== Now,0.056 moles HCl (1 mole Sn/4 moles HCl)(118.7 grams /1 mole Sn)= 1.7 grams of tin-----------------------