One Mole of Sodium Hydroxide
NaOH= 40.00g/l =1N
(8.0g NaOH in 100.0ml of water)= 2N NaOH
or
(80g of NaOH in 1L of water)= 2N NaOH
Sodium when dissolved in water we get sodium hydroxide and hydrogen gas is liberated.
In the formula 2NaOH, the number 2 is called a coefficient. It indicates that there are 2 moles of NaOH present in the compound.
H2SO4+2NaOH------->Na2SO4+H20
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
It is sodium hydroxide.
Sodium when dissolved in water we get sodium hydroxide and hydrogen gas is liberated.
The formula is describing a chemical reaction where 2 molecules of sodium hydroxide (2NaOH) react with chlorine gas (Cl2) to produce sodium chloride (NaCl), sodium hypochlorite (NaClO), and water (H2O).
In the formula 2NaOH, the number 2 is called a coefficient. It indicates that there are 2 moles of NaOH present in the compound.
H2SO4+2NaOH------->Na2SO4+H20
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
the balanced equation is Na2S2O3 plus H2O2 yields 2NaOH plus H2S2O3 plus O2.
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
The balanced equation for the reaction of sodium with water is: 2Na (s) + 2H2O (l) -> 2NaOH (aq) + H2 (g)
K2SO4 + 2NaOH ==> Na2SO4 + 2KOH
2Na+2H2O------>2NaOH+H2
Cu(NO3)2 + 2NaOH >> Cu(OH)2 + 2NaNO3