Cu(NO3)2 + 2NaOH >> Cu(OH)2 + 2NaNO3
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
Ca(NO3)2 , Calcium nitrate Nitric acid + Calcium hydroxide ----> Calcium Nitrate + Water 2HNO3 + Ca(OH)2 ---> Ca(NO3)2 + 2H2O
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate
The chemical reaction is: NH4NO3 + NaOH -----→ NH3 + H2O + NaNO3
The chemical reaction is: NH4NO3 + NaOH ---------→ NH3 + H2O + NaNO3
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
2Na3PO4 + 3Ca(NO3)2 --> 6NaNO3 + Ca3(PO4)2
Ca(NO3)2 + 2Li --> 2LiNO3 + Ca 2+
In a standard double replacement reaction, you would have the following equation: Cu(NO3)2 + 2NH4OH -----> Cu(OH)2 + 2NH4NO3 Therefore, your products would be copper II hydroxide and ammonium nitrate.
No reaction
No balance
Ca(NO3)2 + 2NaOH >> Ca(OH)2 + 2NaNO3