3H2O + SO4 is not a defined chemical formula. 3H2O represents 3 water molecules and SO4 represents sulfate. The reaction or compound formed would depend on the specific conditions under which these substances are combined.
When ferric oxide (Fe3O2) reacts with sulfuric acid (H2SO4), it forms ferric sulfate (Fe2(SO4)3) and water (H2O). The balanced equation for this reaction is: Fe3O2 + 3H2SO4 → 2Fe2(SO4)3 + 3H2O.
AL(OH)3 + 3HNO3 = AL(NO3)3 + 3H2O pinkey
There are a total of 5 atoms in the sulfate ion (SO4), consisting of 1 sulfur atom and 4 oxygen atoms.
Fe2(SO4)3, iron (III) sulfate, is not an element but rather a compound.
It is: C2H5OH+3O2 ----> 2CO2+3H2O
Yes, chromium(III) sulfate can be made by reacting chromium(III) oxide with sulfuric acid. The chemical equation is: Cr2O3 + 3H2SO4 → Cr2(SO4)3 + 3H2O. The resulting compound is chromium(III) sulfate with the formula Cr2(SO4)3.
When ferric oxide (Fe3O2) reacts with sulfuric acid (H2SO4), it forms ferric sulfate (Fe2(SO4)3) and water (H2O). The balanced equation for this reaction is: Fe3O2 + 3H2SO4 → 2Fe2(SO4)3 + 3H2O.
2NaAlO 2+3h2O
AL(OH)3 + 3HNO3 = AL(NO3)3 + 3H2O pinkey
3H2O has 6 hydrogen atoms and 3 oxygen atoms.
SO4 is not a molecule. (SO4)2- is the sulfate ion.
Sulphuric Acid:- H2SO4 Aluminium Hydroxide:- Al(OH)3
BeC2O4 = 97.0 g/1 mol BeC2O4-3H2O = 151.0 g/1 mol 3.21 g BeC2O4-3H2O * 1 mol/151.0 g = 0.021258 mol BeC2O4-3H2O 0.021258 mol BeC2O4-3H2O * 97.0 g/1 mol = 2.06 g BeC2O4
It is SO4 -2 named as sulphate ion.
Ba(SO4) + 2KCl
SO4 is the chemical formula for the anion sulfate.
Aluminum sulfate is formulated by Al2(SO4)3