Just add the two masses: 40 + 120 = 160 grams.
Approximately 73.2 grams of copper sulphate can be dissolved in 50 grams of water at 60 degrees Celsius. This is the maximum amount of copper sulphate that the water can hold in a saturated solution at that temperature.
The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.
Approximately 39 grams of sodium chloride can be dissolved in 100 grams of water at 95 degrees Celsius.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
The mass of the solution would be the sum of the mass of the sodium chloride and the mass of water. So, the mass of the solution would be 17.8 grams (NaCl) + 217 grams (water) = 234.8 grams.
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
To find the molarity, we first calculate the number of moles of copper chloride using its molar mass. The molar mass of copper chloride is 134.45 g/mol. Then divide the mass by the number of moles and the volume in liters (1500 mL = 1.5 L) to get the molarity. The molarity of the solution is 0.20 M.
Approximately 73.2 grams of copper sulphate can be dissolved in 50 grams of water at 60 degrees Celsius. This is the maximum amount of copper sulphate that the water can hold in a saturated solution at that temperature.
The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.
The component water is the solvent in this case.
Approximately 39 grams of sodium chloride can be dissolved in 100 grams of water at 95 degrees Celsius.
The answer is 15,039 g hydrogen chloride (HCl).
After 50 grams of water evaporate, you will be left with 50 grams of water in which the 3.0 grams of salt is dissolved. So, your solution will now contain 3.0 grams of salt dissolved in 50 grams of water.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
You would have a saturated solution because at that temperature and concentration, the amount of sodium chloride being dissolved is in equilibrium with the amount that can be dissolved. Any more added would exceed its solubility.
Not exactly. Saline solution is sterilized and is a dilution of sodium chloride (NaCl) - meaning that the NaCl is dissolved in deionized water. The solution is 9 grams of sodium chloride (NaCl) dissolved in 1 liter of water.
4 milliequivalents of sodium chloride solution is a solution having 0,2338 g in 1 L.