It would produce a solution of acetic acid.
carbon oxygen hydrogen = CH3COOH is the thingy for vinegar
When acetic acid (CH3COOH) reacts with ethanol (CH3CH2OH), they undergo esterification to produce ethyl acetate (CH3COOCH2CH3) and water (H2O). This reaction is catalyzed by an acid, usually sulfuric acid. Ethyl acetate is a sweet-smelling ester commonly used as a solvent.
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
The reaction between aqueous acetic acid (CH3COOH) and aqueous sodium hydroxide (NaOH) forms water (H2O) and sodium acetate (CH3COONa). The balanced chemical equation is: CH3COOH + NaOH -> H2O + CH3COONa
CH3COOH+NH4OH turns into H2O+CH3COONH4 have fun with chem
Ch3coo(-) + h2o ---> ch3cooh + oh(-)
its balanced
CH3CH2OOCCH3 + H2O ===> CH3CH2OH + CH3COOH
Dissolving in water = splitting in ionsCH3COONH4 --> CH3COO- + NH4+CH3COO-, acetate is a weak base: CH3COO- + H2O CH3COOH + OH-NH4+, ammonium is a weak acid: NH4+ + H2O NH3 + H3O+Totally in water: CH3COO- + NH4+ CH3COOH + NH3 and 2H2O H3O+ + OH-
carbon oxygen hydrogen = CH3COOH is the thingy for vinegar
NaOH + CH3COOH = CH3COONa + H2O Good Luck !
CH3COOH + OH ---> CH3COO + H2O CH3COOH stays as a molecule because it is a weak acid
When acetic acid (CH3COOH) reacts with ethanol (CH3CH2OH), they undergo esterification to produce ethyl acetate (CH3COOCH2CH3) and water (H2O). This reaction is catalyzed by an acid, usually sulfuric acid. Ethyl acetate is a sweet-smelling ester commonly used as a solvent.
The reaction between aqueous acetic acid (CH3COOH) and aqueous sodium hydroxide (NaOH) forms water (H2O) and sodium acetate (CH3COONa). The balanced chemical equation is: CH3COOH + NaOH -> H2O + CH3COONa
CH3COOH+NH4OH turns into H2O+CH3COONH4 have fun with chem
CH3COOH + KOH = CH3COOK + H2O
The balanced chemical equation for the reaction between acetic acid (HC2H3O2) and sodium hydroxide (NaOH) is: HC2H3O2 + NaOH → NaC2H3O2 + H2O This reaction forms sodium acetate (NaC2H3O2) and water (H2O).