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Is CuC2H3O2 a ionic compound or a molecular?
CuC2H3O2 is a molecular compound. It is made up of covalent bonds between the elements in the compound, including copper, carbon, and hydrogen.
Write the ions present in solution of Cu C2H3O2 2 and identify all of the phases in your answers?
In solution, CuC2H3O2 would dissociate into Cu2+ and C2H3O2- ions. The phases involved would be solid CuC2H3O2 dissociating into aqueous Cu2+ and C2H3O2- ions.
When acetic acid combines with copper it makes copper acetate and what?
It creates Copper Acetate and Hydrogen shown by the following balanced equation. 2HC2H3O2 + Cu ---> Cu(C2H3O2)2 + H2 but.......................................... wouldn't the answer be... ? HC2H3O2 + Cu ---> CuC2H3O2 + H2O [<< water is always produced in a acid reaction?] ^Where's your extra oxygen coming from? Water and a salt are always produced as reactants in acid - base reactions, acid - metal reactions almost always involve some sort of ionic reaction with H2 as a product, the original equation is correct.
Is CuC2H3O2 a ionic compound or a molecular?
CuC2H3O2 is a molecular compound. It is made up of covalent bonds between the elements in the compound, including copper, carbon, and hydrogen.
Write the ions present in solution of Cu C2H3O2 2 and identify all of the phases in your answers?
In solution, CuC2H3O2 would dissociate into Cu2+ and C2H3O2- ions. The phases involved would be solid CuC2H3O2 dissociating into aqueous Cu2+ and C2H3O2- ions.
When acetic acid combines with copper it makes copper acetate and what?
It creates Copper Acetate and Hydrogen shown by the following balanced equation. 2HC2H3O2 + Cu ---> Cu(C2H3O2)2 + H2 but.......................................... wouldn't the answer be... ? HC2H3O2 + Cu ---> CuC2H3O2 + H2O [<< water is always produced in a acid reaction?] ^Where's your extra oxygen coming from? Water and a salt are always produced as reactants in acid - base reactions, acid - metal reactions almost always involve some sort of ionic reaction with H2 as a product, the original equation is correct.
